从字符串中获取数据

I have this as a string. I have get this using jquery and parsing it from a web page.

我把它作为一个字符串。我使用jquery并从网页解析它。

I tried using jQuery.parseJSON and got the error Uncaught SyntaxError: Unexpected token n.

我尝试使用jQuery.parseJSON并得到错误Uncaught SyntaxError:Unexpected token n。

I need to get "surl" and "imgurl" how can I get this?

我需要得到“surl”和“imgurl”我怎么能得到这个?

{
    ns:"images",
    k:"5061",
    mid:"172E23D582B8C2A90F3FE9DC2B04A3ECD1D4F70F",
    surl:"http://polyhouse2011.wordpress.com/2011/05/16/safety-precautions-2/",
    imgurl:"http://polyhouse2011.files.wordpress.com/2011/05/safety_gear1.gif",
    ow:"480",
    docid:"608038082569896450",
    oh:"301",
    tft:"117",
    dls:"images,5487"
}

Source of this string:

这个字符串的来源:

<a href="#" q="{ns:"images",k:"5061",mid:"172E23D582B8C2A90F3FE9DC2B04A3ECD1D4F70F",surl:"http://polyhouse2011.wordpress.com/2011/05/16/safety-precautions-2/",imgurl:"http://polyhouse2011.files.wordpress.com/2011/05/safety_gear1.gif",ow:"480",docid:"608038082569896450",oh:"301",tft:"117",dls:"images,5487"}"></a>

4 个解决方案

#1

My example assumes your anchor has an id for convenience. If you use wrxsti's answer without all the unnecessary escaping, you get this:

我的例子假设你的锚有一个方便的id。如果你使用wrxsti的答案而没有所有不必要的转义,你得到这个:

var str = document.getElementById('a').getAttribute('q');
var json = JSON.stringify(eval("(" + str + ")"));
var obj = JSON.parse(json)
var surl = obj.srl;

DEMO

But you really should get that attribute data changed to proper parsing JSON.

但是你真的应该将属性数据改为正确解析JSON。

#2

If you do not have the option of editing the JSON information you can do this to make it a valid json object. I will say that including eval can be bad due to security reasons, but this will make your JSON a valid object in the long run.

如果您没有编辑JSON信息的选项,则可以执行此操作以使其成为有效的json对象。我会说,由于安全原因,包括eval可能会很糟糕,但从长远来看,这将使你的JSON成为一个有效的对象。

var object = '{ \
    ns: "images", \
    k: "5061", \
    mid: "172E23D582B8C2A90F3FE9DC2B04A3ECD1D4F70F", \
    surl: "http://polyhouse2011.wordpress.com/2011/05/16/safety-precautions-2/", \
    imgurl: "http://polyhouse2011.files.wordpress.com/2011/05/safety_gear1.gif", \
    ow: "480", \
    docid: "60808082569896450", \
    oh: "301", \
    tft: "117", \
    dls: "images5487" \
}';

var json = JSON.stringify(eval("(" + object + ")"));
var o = $.parseJSON(json);

DEMO

Hope this helps. Let me know if you have any questions!

希望这可以帮助。如果您有任何疑问,请告诉我!

#3

this is a valid your JSON string :

这是一个有效的JSON字符串:

{
    "ns": "images",
    "k": "5061",
    "mid": "172E23D582B8C2A90F3FE9DC2B04A3ECD1D4F70F",
    "surl": "http://polyhouse2011.wordpress.com/2011/05/16/safety-precautions-2/",
    "imgurl": "http://polyhouse2011.files.wordpress.com/2011/05/safety_gear1.gif",
    "ow": "480",
    "docid": "608038082569896450",
    "oh": "301",
    "tft": "117",
    "dls": "images,5487"
}

if you get some error in your JSON string then check its validation online through http://jsonlint.com/ i hope it will help you.

如果您的JSON字符串中出现错误,请通过http://jsonlint.com/在线查看其验证,我希望它能为您提供帮助。

#4

You use object format not json format, it is correct if you do like the following code:

您使用对象格式而不是json格式,如果您喜欢以下代码,则它是正确的:

var obj = {
    ns:"images",
    k:"5061",
    mid:"172E23D582B8C2A90F3FE9DC2B04A3ECD1D4F70F",
    surl:"http://polyhouse2011.wordpress.com/2011/05/16/safety-precautions-2/",
    imgurl:"http://polyhouse2011.files.wordpress.com/2011/05/safety_gear1.gif",
    ow:"480",
    docid:"608038082569896450",
    oh:"301",
    tft:"117",
    dls:"images,5487"
}

Therefore, if you want to get surl and imgurl: just do: obj.surl; and obj.imgurl

因此,如果你想获得surl和imgurl:只需:obj.surl;和obj.imgurl