本文实例为大家分享了python实现转圈打印矩阵的具体代码,供大家参考,具体内容如下
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#! conding:utf-8
__author__ = "hotpot"
__date__ = "2017/10/28 9:40"
def return_edge(matrix, start_col, end_col, start_row, end_row):
if start_row = = end_row:
return matrix[start_row][start_col:end_col + 1 ]
elif end_col = = start_col:
res = []
for i in range (start_row,end_row + 1 ):
res.append(matrix[i][end_col])
return res
else :
res2 = []
res3 = []
res4 = []
res1 = matrix[start_row][start_col:end_col + 1 ]
for i in range (start_row + 1 ,end_row + 1 ):
res2.append(matrix[i][end_col])
for i in range (end_col - 1 ,start_col - 1 , - 1 ):
res3.append(matrix[end_row][i])
for i in range (end_row - 1 ,start_row, - 1 ):
res4.append(matrix[i][start_row])
res1.extend(res2)
res1.extend(res3)
res1.extend(res4)
return res1
def spiralOrder( matrix):
if matrix:
row = len (matrix) - 1
col = len (matrix[ 0 ]) - 1
start_row = 0
start_col = 0
end_row = row
end_col = col
res = []
while start_col< = end_col and start_row < = end_row:
res.extend(return_edge(matrix,start_col,end_col , start_row ,end_row))
start_col + = 1
end_col - = 1
start_row + = 1
end_row - = 1
return res
else :
return matrix
if __name__ = = '__main__' :
matrix = [[ 0 for i in range ( 3 ) ] for j in range ( 3 )]
num = 1
for m in range ( len (matrix)):
for n in range ( len (matrix[ 0 ])):
matrix[m][n] = num
num + = 1
print (spiralOrder( matrix))
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以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持服务器之家。
原文链接:https://blog.csdn.net/hotpotbo/article/details/78374025