比如table1的列为 id, user_id, type_id,pro_id;
table2的列为 id,user_id,collect_id;分别如下图所示
table1:
table2:
将两个表的查询结果合并到一起的查询语句为
1
2
3
|
select *, null as collect_id from table1 where user_id = 527
union
select id,user_id, null as type_id, null as pro_id, collect_id from table2 where user_id = 527;
|
结果为:
其实就是把对应的列补充到没有该列的表中,在例子中就是把collect_id补充到table1中,
把type_id,pro_id补充到table2中。
补充知识:sql结果集合并用union all 不同表的列合并用join
结果集合并用union all 不同表的列合并用join
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
|
SELECT
"模块名" ,
"事件编码" ,
"点击数量" ,
"使用时长(单位:分)"
FROM
( SELECT
T.fun_name as "模块名" ,
T.event_code as "事件编码" ,
SUM (click_records) as "点击数量"
FROM
( SELECT m.* FROM default .daily_new_clientrpt_master m WHERE event_id in ( SELECT max (event_id) AS "事件" from default .daily_new_clientrpt_master group by user_name,fun_code ORDER BY "事件" DESC ) ) T where day = today() GROUP BY "模块名" , "事件编码" ) T5
JOIN
(
SELECT
T.fun_name as "模块名" ,
T.event_code as "事件编码" ,
round( sum (stay_time)/60000,0) as "使用时长(单位:分)"
FROM
( SELECT m.* FROM default .daily_new_clientrpt_master m WHERE event_id in
(
SELECT "事件" FROM (
SELECT max (event_id) AS "事件" , max (stay_time) AS "事件1" from default .daily_new_clientrpt_master group by user_name,fun_code ORDER BY "事件1" DESC ) )
)
T where day = today() AND like (event_code, '%10000' ) GROUP BY "模块名" , "事件编码"
) T6 ON T5. "模块名" =T6. "模块名" AND T5. "事件编码" =T6. "事件编码"
|
以上这篇SQL 列不同的表查询结果合并操作就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持服务器之家。
原文链接:https://blog.csdn.net/u010498402/article/details/78038553