Oracle PL/SQL:从字符串中删除“空格字符”

In my Oracle 10g database I would like to remove "space characters" (spaces, tabs, carriage returns...) from the values of a table field.

在Oracle 10g数据库中，我希望从表字段的值中删除“空间字符”(空格、制表符、回车符…)。

Is TRANSLATE() the way to go ? For example something like:

翻译是正确的方法吗?例如像:

MY_VALUE := TRANSLATE(MY_VALUE,
  CHR(9) || CHR(10) || CHR(11) || CHR(12) || CHR(13) || ' ', '');

Or is there any better alternative (something like [:space:] in PHP PCRE) ?

或者有没有更好的选择(比如:在PHP PCRE中)?

Thanks for any piece of advice.

谢谢你的任何建议。

6 个解决方案

#1

I'd go for regexp_replace, although I'm not 100% sure this is usable in PL/SQL

我选择regexp_replace，尽管我不能100%确定它在PL/SQL中是否可用

my_value := regexp_replace(my_value, '[[:space:]]*','');

#2

Shorter version of:

短版的:

REGEXP_REPLACE( my_value, '[[:space:]]', '' )

Would be:

是:

REGEXP_REPLACE( my_value, '\s')

Neither of the above statements will remove "null" characters.

上述任何一条语句都不会删除“null”字符。

To remove "nulls" encase the statement with a replace

要删除“nulls”，请使用替换将语句括起来

Like so:

像这样:

REPLACE(REGEXP_REPLACE( my_value, '\s'), CHR(0))

#3

Since you're comfortable with regular expressions, you probably want to use the REGEXP_REPLACE function. If you want to eliminate anything that matches the [:space:] POSIX class

由于您熟悉正则表达式，您可能希望使用REGEXP_REPLACE函数。如果您想消除任何与[:space:] POSIX类匹配的内容

REGEXP_REPLACE( my_value, '[[:space:]]', '' )


SQL> ed
Wrote file afiedt.buf

  1  select '|' ||
  2         regexp_replace( 'foo ' || chr(9), '[[:space:]]', '' ) ||
  3         '|'
  4*   from dual
SQL> /

'|'||
-----
|foo|

If you want to leave one space in place for every set of continuous space characters, just add the + to the regular expression and use a space as the replacement character.

如果要为每组连续空格字符保留一个空格，只需将+添加到正则表达式中，并使用空格作为替换字符。

with x as (
  select 'abc 123  234     5' str
    from dual
)
select regexp_replace( str, '[[:space:]]+', ' ' )
  from x

#4

select regexp_replace('This is a test   ' || chr(9) || ' foo ', '[[:space:]]', '') from dual;

REGEXP_REPLACE
--------------
Thisisatestfoo

#5

To remove any whitespaces you could use:

删除任何你可以使用的空白:

myValue := replace(replace(replace(replace(replace(replace(myValue, chr(32)), chr(9)),  chr(10)), chr(11)), chr(12)), chr(13));

Example: remove all whitespaces in a table:

示例:删除表中的所有白空间:

update myTable t
    set t.myValue = replace(replace(replace(replace(replace(replace(t.myValue, chr(32)), chr(9)), chr(10)), chr(11)), chr(12)), chr(13))
where
    length(t.myValue) > length(replace(replace(replace(replace(replace(replace(t.myValue, chr(32)), chr(9)), chr(10)), chr(11)), chr(12)), chr(13)));

或

update myTable t
    set t.myValue = replace(replace(replace(replace(replace(replace(t.myValue, chr(32)), chr(9)), chr(10)), chr(11)), chr(12)), chr(13))
where
    t.myValue like '% %'

#6

To replace one or more white space characters by a single blank you should use {2,} instead of *, otherwise you would insert a blank between all non-blank characters.

要将一个或多个空格字符替换为一个空格，您应该使用{2，}而不是*，否则将在所有非空格字符之间插入空格。

REGEXP_REPLACE( my_value, '[[:space:]]{2,}', ' ' )

#1