I'm trying to pass the values of array to php but i can not get the values. It returns NULL, when I use var_dump() it returns array(1) { [0]=> string(0) "" } Array ( [0] => )
我试图将数组的值传递给php,但我不能得到值。它返回NULL,当我使用var_dump()时它返回数组(1){[0]=>字符串(0)"}数组([0]=>)
Here the code:
下面的代码:
$("#submit").click(function () {
var newhour= [];
for (var i = 0; i < arrayNumbers.length; i++) {
newhour.push(arrayNumbers[i].toString().split(','));
console.log("each: " + newhour[i]); // output: each: 07:00,08:30
each: 18:00,19:00
}
console.log("all: " + newhour); //output: all: 07:00,08:30,18:00,19:00
var jsonx = JSON.stringify(newhour);
console.log("x: " +jsonx); // output: x: [["07:00","08:30"],["18:00","19:00"]]
$.ajax({
type: "POST",
url: "hour.php",
data:{data: jsonx},
cache: false,
success: function(){
alert("OK");
}
});
});
hour.php file include:
小时。php文件包括:
$data = json_decode($_POST['data'],true);
//$data = json_decode(($_POST['data']));
//$data = explode(",", $_POST['data']);
//$data = $_POST['data'];
echo "data: " .$data;
var_dump($data);
foreach($data as $d){
echo $d;
}
I struggled with that for hours, i tried everything but couldn't get any values. I don not understand where I'm wrong. Can you please help me with my code? Thanks in advance.
我挣扎了好几个小时,什么都试过了,但没有任何价值。我不明白我错在哪里。你能帮我写代码吗?提前谢谢。
1 个解决方案
#1
0
It works fine for me This is the data I used for arrayNumbers
这对我来说很好,这是我用于arrayNumbers的数据。
var arrayNumbers = [1, 591, 283, 12];
var arrayNumbers = [1,591, 283,12];
This is the return data
这是返回数据。
data: Arrayarray(4) { [0]=> array(1) { [0]=> string(1) "1" } [1]=> array(1) { [0]=> string(3) "591" } [2]=> array(1) { [0]=> string(3) "283" } [3]=> array(1) { [0]=> string(2) "12" } } ArrayArrayArrayArray
数据:Arrayarray(4){[0]= >数组(1){[0]= >字符串(1)"1"}[1]=>数组(1){[0]=>字符串(3)"591"}[2]=>数组(1){[0]=>字符串(3)"283"}[3]=>数组(1){[0]=>字符串(2)} } ArrayArrayArrayArray“12”
EDIT: just tried a few different values for arrayNumbers. When i used var arrayNumbers = [""];
I got your exact return. Check what values you are using for that because thats the issue.
编辑:只是为arrayNumbers尝试了几个不同的值。当我使用var arrayNumbers = ["];我得到了你的确切回报。检查你所使用的值,因为这是问题所在。
Note: I also had to comment out each: 18:00,19:00
, but I assumed you already had that commented and copied it wrong
注意:我也不得不注释掉每一个:18:00,19:00,但是我假设你已经有了这个评论并把它抄错了。
#1
0
It works fine for me This is the data I used for arrayNumbers
这对我来说很好,这是我用于arrayNumbers的数据。
var arrayNumbers = [1, 591, 283, 12];
var arrayNumbers = [1,591, 283,12];
This is the return data
这是返回数据。
data: Arrayarray(4) { [0]=> array(1) { [0]=> string(1) "1" } [1]=> array(1) { [0]=> string(3) "591" } [2]=> array(1) { [0]=> string(3) "283" } [3]=> array(1) { [0]=> string(2) "12" } } ArrayArrayArrayArray
数据:Arrayarray(4){[0]= >数组(1){[0]= >字符串(1)"1"}[1]=>数组(1){[0]=>字符串(3)"591"}[2]=>数组(1){[0]=>字符串(3)"283"}[3]=>数组(1){[0]=>字符串(2)} } ArrayArrayArrayArray“12”
EDIT: just tried a few different values for arrayNumbers. When i used var arrayNumbers = [""];
I got your exact return. Check what values you are using for that because thats the issue.
编辑:只是为arrayNumbers尝试了几个不同的值。当我使用var arrayNumbers = ["];我得到了你的确切回报。检查你所使用的值,因为这是问题所在。
Note: I also had to comment out each: 18:00,19:00
, but I assumed you already had that commented and copied it wrong
注意:我也不得不注释掉每一个:18:00,19:00,但是我假设你已经有了这个评论并把它抄错了。