如何将对象数组从javascript传递到PHP

If I have, in javascript, something like:

如果我有，在javascript，类似:

entriesObj1 = new Object();
entriesObj1.entryId = "abc";
entriesObj1.mediaType = 2;
entriesObj2 = new Object();
entriesObj2.entryId = "def";
entriesObj2.mediaType = 1;

var entries = new Array();

entries[0] = entriesObj1;
entries[1] = entriesObj2;

What is the best method to pass it to php through an HTTP POST?

通过HTTP POST将其传递给php的最佳方法是什么?

I've tried a jQuery plugin to convert the array to JSON. I've tried to create multiple hidden fields named "entries[]", each one with the JSON string. Somehow, I can't seem to decode my data with PHP's json_decode.

我尝试了一个jQuery插件将数组转换为JSON。我尝试创建多个名为“entries[]”的隐藏字段，每个字段都带有JSON字符串。不知何故，我似乎无法用PHP的json_decode解码我的数据。

EDIT: I tried changing the JSON plugin used to the one @Michal indicated and the results I get are the same:

编辑:我尝试将JSON插件改为@Michal所示，结果是一样的:

Javascript

[
    {"disciplina":"sdfsdfsdfsd","titulo":"sdfsdfsdf","componentes":"Bloco Completo"},
    {"disciplina":"sdfsdfsdfsd","titulo":"sdfsdfsdf","componentes":"Bloco Completo"}    
]

PHP Vardump:

string(756) "
[
    {\"disciplina\":\"sdfsdfsdfsd\",\"titulo\":\"sdfsdfsdf\",\"componentes\":\"Bloco Completo\"},
    {\"disciplina\":\"sdfsdfsdfsd\",\"titulo\":\"sdfsdfsdf\",\"componentes\":\"Bloco Completo\"}
]
"

When I use PHP's json_decode, I get NULL.

当我使用PHP的json_decode时，我得到NULL。

var_dump(json_decode($_REQUEST['entries']));

Output:

输出:

NULL

3 个解决方案

#1

You need to convert JSON to a string (use JSON stringifier (https://github.com/douglascrockford/JSON-js) and POST the string (as a field value) to the PHP script which does json_decode()

您需要将JSON转换为字符串(使用JSON stringifier (https://github.com/douglas douglas crockford/json -js)并将字符串(作为字段值)POST到PHP脚本，该脚本执行json_decode()

#2

Concat it using some characters like _ or %% then pass it to PHP.

使用_或%%等字符进行Concat，然后将其传递给PHP。

In PHP file:

在PHP文件:

$ar = array();
$ar = explode('special_char',string pass from js);
echo "pre";print_r($ar);
echo "/pre";

#3

well, the trouble seemed to be with the quotes that were being passed in the post, so i just replaced the quotes with open strings to my $_REQUEST.

问题似乎在于post中传递的引号，所以我只是将引号替换为open string以满足$_REQUEST。

#1