I have an ajax call from javascript to a method in a controller, the method in the controller should be loading a view(like, show a new page on the screen), Although everything seems ok, the new view doesn't seem to load on the screen. I cannot use header or windows.location because, i am passing an array variable, containing data to be used in the view.
我有一个从javascript到控制器中的方法的ajax调用,控制器中的方法应该加载一个视图(比如,在屏幕上显示一个新页面),虽然一切似乎都没问题,新视图似乎没有加载屏幕上。我不能使用header或windows.location,因为我传递的数组变量包含要在视图中使用的数据。
The page is visible under the Network tab (preview sub tab, while selecting the ajax) of the Chrome debugging console. But the main screen stays as it is.
该页面在Chrome调试控制台的“网络”选项卡(预览子选项卡,同时选择ajax)下可见。但主屏幕保持不变。
If somebody has faced a similar issue, or has a solution, please help me.
如果有人遇到类似的问题,或者有解决方案,请帮助我。
Thanks!!
谢谢!!
3 个解决方案
#1
9
Ok here is what you are doing wrong.
好的,这就是你做错了。
when you request the page using ajax it does not return you that page.
当您使用ajax请求页面时,它不会返回该页面。
when you use $this->load->view('pagename',$datapassed); it loads the view and thats why you see nothing.
当你使用$ this-> load-> view('pagename',$ datapassed);它加载视图,这就是为什么你什么也看不见。
What you have to do is use
你要做的就是使用
$data=$this->load->view('pagename',$datapassed, TRUE);
what it will do is it will return that page and save it in $data after that you can print it using
它会做什么,它将返回该页面并将其保存在$ data中,之后您可以使用它来打印它
$this->set_output($data);
and receive this in ajax result and load it in a div.
并在ajax结果中接收它并将其加载到div中。
and if you want to refresh the whole page you can use
如果你想刷新整个页面,你可以使用
$(body).html(result);
You have to understand that you need to send the html page by supplying that third parameter in load view.
您必须了解您需要通过在加载视图中提供第三个参数来发送html页面。
#2
4
In controller class
在控制器类中
function get_view_ajax()
{
$data['username] = $_POST['username];
$response = $this->load->view('radius/radius_corporate_graph',$data,TRUE);
echo $response;
}
In view file where you initiate ajax call
在视图文件中,您启动ajax调用
$('#button').click(function(){
var username = $('#username').val();
$.ajax({
type:'POST',
url:"<?php echo base_url(); ?>controller_name/get_view_ajax/",
data: "username="+username,
success:function(msg){
$("#div_result").html(msg);
},
error: function(result)
{
$("#div_result").html("Error");
},
fail:(function(status) {
$("#div_result").html("Fail");
}),
beforeSend:function(d){
$('#div_result').html("<center><strong style='color:red'>Please Wait...<br><img height='25' width='120' src='<?php echo base_url();?>img/ajax-loader.gif' /></strong></center>");
}
});
});
<div id="div_result">
<a href="#" id="button">Click here </a>
Another view file to be loaded on controller function (extra_info.php) as refered on get_view_ajax function
另一个要在控制器函数(extra_info.php)上加载的视图文件,它引用了get_view_ajax函数
<h1>This page is called from ajax function </h1>
#3
0
Keep in mind dataType must be "html"
请记住dataType必须是“html”
$.ajax({ type: 'POST', url: '/controllerName/functionName', dataType: "html", success: function (response) { $("#oh").html(response); }, error: function (error_) { MYLOG(error_); } });
$ .ajax({type:'POST',url:'/ controllerName / functionName',dataType:“html”,success:function(response){$(“#oh”)。html(response);},error: function(error_){MYLOG(error_);}});
#1
9
Ok here is what you are doing wrong.
好的,这就是你做错了。
when you request the page using ajax it does not return you that page.
当您使用ajax请求页面时,它不会返回该页面。
when you use $this->load->view('pagename',$datapassed); it loads the view and thats why you see nothing.
当你使用$ this-> load-> view('pagename',$ datapassed);它加载视图,这就是为什么你什么也看不见。
What you have to do is use
你要做的就是使用
$data=$this->load->view('pagename',$datapassed, TRUE);
what it will do is it will return that page and save it in $data after that you can print it using
它会做什么,它将返回该页面并将其保存在$ data中,之后您可以使用它来打印它
$this->set_output($data);
and receive this in ajax result and load it in a div.
并在ajax结果中接收它并将其加载到div中。
and if you want to refresh the whole page you can use
如果你想刷新整个页面,你可以使用
$(body).html(result);
You have to understand that you need to send the html page by supplying that third parameter in load view.
您必须了解您需要通过在加载视图中提供第三个参数来发送html页面。
#2
4
In controller class
在控制器类中
function get_view_ajax()
{
$data['username] = $_POST['username];
$response = $this->load->view('radius/radius_corporate_graph',$data,TRUE);
echo $response;
}
In view file where you initiate ajax call
在视图文件中,您启动ajax调用
$('#button').click(function(){
var username = $('#username').val();
$.ajax({
type:'POST',
url:"<?php echo base_url(); ?>controller_name/get_view_ajax/",
data: "username="+username,
success:function(msg){
$("#div_result").html(msg);
},
error: function(result)
{
$("#div_result").html("Error");
},
fail:(function(status) {
$("#div_result").html("Fail");
}),
beforeSend:function(d){
$('#div_result').html("<center><strong style='color:red'>Please Wait...<br><img height='25' width='120' src='<?php echo base_url();?>img/ajax-loader.gif' /></strong></center>");
}
});
});
<div id="div_result">
<a href="#" id="button">Click here </a>
Another view file to be loaded on controller function (extra_info.php) as refered on get_view_ajax function
另一个要在控制器函数(extra_info.php)上加载的视图文件,它引用了get_view_ajax函数
<h1>This page is called from ajax function </h1>
#3
0
Keep in mind dataType must be "html"
请记住dataType必须是“html”
$.ajax({ type: 'POST', url: '/controllerName/functionName', dataType: "html", success: function (response) { $("#oh").html(response); }, error: function (error_) { MYLOG(error_); } });
$ .ajax({type:'POST',url:'/ controllerName / functionName',dataType:“html”,success:function(response){$(“#oh”)。html(response);},error: function(error_){MYLOG(error_);}});