Here I am fetching the data from Wikipedia using following code. but it is not working for me.
这里我使用以下代码从Wikipedia获取数据。但这对我不起作用。
var playListURL = 'http://en.wikipedia.org/w/api.php?format=json&action=query&titles=India&prop=revisions&rvprop=content&callback=?';
$.getJSON(playListURL ,function(data) {
$.each(data.pages, function(i, item) {
alert(i);
});
});
DEMO LINK :- http://jsfiddle.net/rushijogle/dyeqy/
演示链接:http://jsfiddle.net/rushijogle/dyeqy/
3 个解决方案
#1
6
Use the following code to get the data:
使用以下代码获取数据:
$.getJSON(playListURL ,function(data) {
$.each(data.query.pages, function(i, item) {
alert(item.title);
});
});
#2
3
Demo is at http://jsfiddle.net/dyeqy/3/
演示是http://jsfiddle.net/dyeqy/3/
var playListURL = 'http://en.wikipedia.org/w/api.php?format=json&action=query&titles=India&prop=revisions&rvprop=content&callback=?';
$.getJSON(playListURL ,function(data) {
var hash = data
var page_value = ""
$.each(data["query"]["pages"],function(k,v){
alert(k)
$.each(v,function(key,val){
alert(key)
});
});
});
Like this you can take the revisions values also.
像这样,您也可以取修订值。
#3
2
It should be data.query.pages
instead of data.pages
它应该data.query。页面而不是data.pages
工作小提琴
#1
6
Use the following code to get the data:
使用以下代码获取数据:
$.getJSON(playListURL ,function(data) {
$.each(data.query.pages, function(i, item) {
alert(item.title);
});
});
#2
3
Demo is at http://jsfiddle.net/dyeqy/3/
演示是http://jsfiddle.net/dyeqy/3/
var playListURL = 'http://en.wikipedia.org/w/api.php?format=json&action=query&titles=India&prop=revisions&rvprop=content&callback=?';
$.getJSON(playListURL ,function(data) {
var hash = data
var page_value = ""
$.each(data["query"]["pages"],function(k,v){
alert(k)
$.each(v,function(key,val){
alert(key)
});
});
});
Like this you can take the revisions values also.
像这样,您也可以取修订值。
#3
2
It should be data.query.pages
instead of data.pages
它应该data.query。页面而不是data.pages
工作小提琴