大体思路
红包的分发见JAVA作业——红包分发。
而抢红包要解决的是线程问题。
其实比较简单,设定好人数,每个人一个线程,每个线程执行一遍,有红包就抢,没有红包就抢不到,所以run函数中只要判断现在还有没有红包就可以了。
代码实现
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import java.util.Random;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
int person_num, red_pocket_num, sum_money;
Scanner scanner = new Scanner(System.in);
System.out.println( "请设置红包个数:" );
red_pocket_num = scanner.nextInt();
System.out.println( "请设置总金额数量(分):" );
sum_money = scanner.nextInt();
if (sum_money < red_pocket_num) {
System.out.println( "钱不够,退出程序。" );
return ;
}
System.out.println( "请设置抢红包成员个数:" );
person_num = scanner.nextInt();
myRunnable myrunnable = new myRunnable(sum_money,red_pocket_num);
Thread []person = new Thread[person_num];
for ( int i = 0 ; i < person_num; i++) {
person[i] = new Thread(myrunnable);
person[i].setName( "用户" +(i+ 1 ));
person[i].start();
}
}
}
class myRunnable implements Runnable{
private int []red_pocket;
private int num;
private int now_num;
public myRunnable( int money, int num) {
this .red_pocket = new Red_Pocket(money, num).get_red_packets();
this .num = num;
this .now_num = num;
}
@Override
public void run() {
if ( this .num> 0 ){
System.out.println(Thread.currentThread().getName()+ "抢到了红包 " +( this .num- this .now_num+ 1 )+ " : " +red_pocket[-- this .now_num]+ "分" );
}
else {
System.out.println(Thread.currentThread().getName()+ "未抢到红包。" );
}
}
}
class Red_Pocket{
private long seed;
private int money;
private int num;
public int [] get_red_packets() {
if ( this .money < this .num) return new int [ 0 ];
Random random = new Random( this .seed);
this .seed = random.nextLong();
int [] res = new int [ this .num];
double [] temp = new double [ this .num];
double sum = 0 ;
int sum2 = 0 ;
for ( int i = 0 ; i < this .num; i++) {
temp[i] = random.nextDouble();
sum += temp[i];
}
for ( int i = 0 ; i < this .num; i++) {
res[i] = 1 + ( int )(temp[i] / sum * ( this .money - this .num));
sum2 += res[i];
}
res[random.nextInt( this .num)] += this .money - sum2;
return res;
}
private void init() {
this .seed = new Random(System.currentTimeMillis()).nextLong();
}
public Red_Pocket( int money, int num) {
init();
this .money = money;
this .num = num;
}
}
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原文链接:https://blog.csdn.net/Evrse/article/details/112105591