将两个数组中的一个元素分配到另一个数组中

If I have two arrays and I want to get one element of each of them and put it in another array. I want something like this:

如果我有两个数组，我想得到每个数组中的一个元素，然后把它放到另一个数组中。我想要这样的东西:

var array1 = [2, 3, 8];
var array2 = [4, 6, 5];
var array3 = array1[0].push(array2[0]);

so that the output would be: array3 = [2,4]. How can I do that in javascript?

所以输出是:array3 =[2,4]。如何用javascript实现呢?

hint: I know that the push function is used to append element to array, but what I want is to append element from one array to another element from another array. Or, appending the two elements and putting it in array.

提示:我知道push函数用于将元素添加到数组中，但是我想要的是将元素从一个数组添加到另一个数组中。或者，将两个元素附加到数组中。

4 个解决方案

#1

You could just create an array like

你可以创建一个像这样的数组

var array3 = [array1[0], array2[0]]

In your code there are multiple problems

在您的代码中有多个问题

• array1[0] returns a number not a array so it doesn't have the push method
• array1[0]返回一个数字而不是数组，因此它没有push方法
• Even if you use array1.slice(0,1) to get an array with first element, the push() method will return an number(length of the array - 2) so the assignment won't work
• 即使使用array1.slice(0,1)获取具有第一个元素的数组，push()方法也会返回一个数字(数组的长度- 2)，因此赋值将不起作用

so another way is

另一个方法是

var array3 = array1.slice(0,1);
array3.push(array2[0])

#2

I think you are looking for something like this:

我认为你在寻找这样的东西:

var array3 = [];
    array3.push(array1[0]);
    array3.push(array2[0]);

I created an empty new array, and then added elements to it - easy as that!

我创建了一个空的新数组，然后添加了元素——就这么简单!

You may also want to look at the array.splice function :)

您可能还想查看数组。拼接功能:)

#3

This works with as many arrays as you want

这与你想要的数组一样多。

function getArray (n) {
    var newArray = [];
    if (arguments[1][0] instanceof Array) {
        for (var i = 0; i < arguments[1].length; i += 1) {
            newArray.push(arguments[1][i][n]);
        }
    } else {
        for (var i = 1; i < arguments.length; i += 1) {
             newArray.push(arguments[i][n]);
        }
    }
    return newArray;
}

Lemme give you some examples to show you how this works:

让我给你举几个例子，告诉你这是怎么回事:

getArray(index,array1,array2,so on...)

getArray(索引、array1 array2,等等…)

1:

> getArray(0, [1,2,3], [4,5,6])

> getArray(0,(1、2、3),(4、5、6))

[1,4]

(1、4)

2:

> getArray(1, [1,2,3], [4,5,6])

> getArray(1,(1、2、3),(4、5、6))

[2,5]

(2、5)

3:

> getArray(0, [1,2,3], [4,5,6], [7,8,9])

> getArray(0， [1,2,3]， [4,5,6]， [7,8,9])

[1,4,7]

(1、4、7)

4:

getArray(0, [
[1,2,3],
[4,5,6]
])

[1,4]

(1、4)

Your way

According to your description, you can use this like:

根据你的描述，你可以这样使用:

var array1 = [1,2,3];
var array2 = [4,6,5];

var array3 = genArray(0, array1, array2);

#4

jquery slice method is used to returns the array element which you want. for example:

   var fruits = ["Banana", "Orange", "Lemon", "Apple", "Mango"];
   var a = ["fruit","veg"];
   var newarray = fruits.slice(0,1); 
   newarray.push(a[0])
   alert(newarray)

if you want to insert/delete method form array element use splice method. the major difference between : slice method : it return new array element without modified existing array element. it needs two arguments for start & EndIndex. For eg:

如果你想插入/删除方法表单数组元素使用splice方法。slice方法的主要区别在于:它返回新的数组元素而不修改现有的数组元素。它需要两个参数来启动和结束索引。如:

var a[3,4,5]
a.slice(0,1) // it returns [3]

splice method : Deletes and/or inserts elements in an array. Unlike slice(), the splice() method modifies the original array and returns a new array. it needs three arguments and, third argument is optional.The first parameter is the index to start deleting and/or insert elements, the second param is number of elements to remove and third param (optional) is the new elements to be added to the array.For eg:

splice方法:删除和/或插入数组中的元素。与slice()不同，splice()方法修改原始数组并返回一个新的数组。它需要三个参数，第三个参数是可选的。第一个参数是开始删除和/或插入元素的索引，第二个参数是要删除的元素数量，第三个参数(可选)是要添加到数组中的新元素。如:

 Var a = [1,2,5,6]
    var b = [3,4]
    a.splice().apply(a,[2,0].concat(b)) // a insert new element as [1,2,3,4,5,6]

//or if you want replace and append new element below like as:

 a.splice().apply(a,[2,1].concat(b)) // a delete [5] element and return as new array as [1,2,3,4,6]