I have two json arrays like
我有两个json数组
var json1 = [{id:1, name: 'xxx' ...}]
var json2 = [{id:2, name: 'xyz' ...}]
I want them merge in to single arrays
我希望它们合并到单个数组中。
var finalObj = [{id:1, name: 'xxx' ...},{id:2, name: 'xyz' ...}]
Regards
问候
8 个解决方案
#2
36
Upon first appearance, the word "merg" leads one to think you need to use .extend, which is the proper jQuery way to "merge" JSON objects. However, $.extend(true, {}, json1, json2);
will cause all values sharing the same key name to be overridden by the latest supplied in the params. As review of your question shows, this is undesired.
乍一看,“merg”这个词会让人觉得需要使用.extend,这是“合并”JSON对象的合适jQuery方法。然而,美元。扩展(真的,{ },json1 json2);将导致共享相同密钥名的所有值被params中提供的最新值覆盖。回顾你的问题,这是不可取的。
What you seek is a simple javascript function known as .concat. Which would work like:
您需要的是一个简单的javascript函数。concat。这将工作:
var finalObj = json1.concat(json2);
While this is not a native jQuery function, you could easily add it to the jQuery library for simple future use as follows:
虽然这不是一个本机jQuery函数,但您可以轻松地将其添加到jQuery库中,以便将来简单地使用它:
;(function($) {
if (!$.concat) {
$.extend({
concat: function() {
return Array.prototype.concat.apply([], arguments);
}
});
}
})(jQuery);
And then recall it as desired like:
然后按照要求回忆:
var finalObj = $.concat(json1, json2);
You can also use it for multiple array objects of this type with a like:
您也可以将它用于此类的多个数组对象,例如:
var finalObj = $.concat(json1, json2, json3, json4, json5, ....);
And if you really want it jQuery style and very short and sweet (aka minified)
如果你真的想要jQuery风格,很短很甜(也就是缩小版)
;(function(a){a.concat||a.extend({concat:function(){return Array.prototype.concat.apply([],arguments);}})})(jQuery);
;(function($){$.concat||$.extend({concat:function(){return Array.prototype.concat.apply([],arguments);}})})(jQuery);
$(function() {
var json1 = [{id:1, name: 'xxx'}],
json2 = [{id:2, name: 'xyz'}],
json3 = [{id:3, name: 'xyy'}],
json4 = [{id:4, name: 'xzy'}],
json5 = [{id:5, name: 'zxy'}];
console.log(Array(10).join('-')+'(json1, json2, json3)'+Array(10).join('-'));
console.log($.concat(json1, json2, json3));
console.log(Array(10).join('-')+'(json1, json2, json3, json4, json5)'+Array(10).join('-'));
console.log($.concat(json1, json2, json3, json4, json5));
console.log(Array(10).join('-')+'(json4, json1, json2, json5)'+Array(10).join('-'));
console.log($.concat(json4, json1, json2, json5));
});
center { padding: 3em; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<center>See Console Log</center>
jsFiddle
#3
21
You could try merge
你可以尝试合并
var finalObj = $.merge(json1, json2);
#4
5
Since you are using jQuery. How about the jQuery.extend() method?
因为您使用的是jQuery。jQuery.extend()方法怎么样?
http://api.jquery.com/jQuery.extend/
http://api.jquery.com/jQuery.extend/
Description: Merge the contents of two or more objects together into the first object.
描述:将两个或多个对象的内容合并到第一个对象中。
#5
2
Maybe, you can use the array syntax of javascript :
也许可以使用javascript的数组语法:
var finalObj =[json1 , json2]
#6
2
You can do this using Es 6 new feature :
你可以使用Es 6新功能:
var json1 = [{id:1, name: 'xxx' , ocupation : 'Doctor' }];
var json2 = [{id:2, name: 'xyz' ,ocupation : 'SE'}];
var combineJsonArray = [...json1 , ...json2];
//output should like this [ { id: 1, name: 'xxx', ocupation: 'Doctor' },
{ id: 2, name: 'xyz', ocupation: 'SE' } ]
Or You can put extra string or anything between two json array :
或者可以在两个json数组之间放置额外的字符串或任何内容:
var json3 = [...json1 ,"test", ...json2];
// output should like this : [ { id: 1, name: 'xxx', ocupation: 'Doctor' },
'test',
{ id: 2, name: 'xyz', ocupation: 'SE' } ]
#7
-1
Try the code below, using jQuery extend method:
尝试以下代码,使用jQuery扩展方法:
var json1 = {"name":"ramesh","age":"12"};
var json2 = {"member":"true"};
document.write(JSON.stringify($.extend(true,{},json1,json2)))
#8
-2
var json1=["Chennai","Bangalore"];
var json2=["TamilNadu","Karanataka"];
finaljson=json1.concat(json2);
#1
#2
36
Upon first appearance, the word "merg" leads one to think you need to use .extend, which is the proper jQuery way to "merge" JSON objects. However, $.extend(true, {}, json1, json2);
will cause all values sharing the same key name to be overridden by the latest supplied in the params. As review of your question shows, this is undesired.
乍一看,“merg”这个词会让人觉得需要使用.extend,这是“合并”JSON对象的合适jQuery方法。然而,美元。扩展(真的,{ },json1 json2);将导致共享相同密钥名的所有值被params中提供的最新值覆盖。回顾你的问题,这是不可取的。
What you seek is a simple javascript function known as .concat. Which would work like:
您需要的是一个简单的javascript函数。concat。这将工作:
var finalObj = json1.concat(json2);
While this is not a native jQuery function, you could easily add it to the jQuery library for simple future use as follows:
虽然这不是一个本机jQuery函数,但您可以轻松地将其添加到jQuery库中,以便将来简单地使用它:
;(function($) {
if (!$.concat) {
$.extend({
concat: function() {
return Array.prototype.concat.apply([], arguments);
}
});
}
})(jQuery);
And then recall it as desired like:
然后按照要求回忆:
var finalObj = $.concat(json1, json2);
You can also use it for multiple array objects of this type with a like:
您也可以将它用于此类的多个数组对象,例如:
var finalObj = $.concat(json1, json2, json3, json4, json5, ....);
And if you really want it jQuery style and very short and sweet (aka minified)
如果你真的想要jQuery风格,很短很甜(也就是缩小版)
;(function(a){a.concat||a.extend({concat:function(){return Array.prototype.concat.apply([],arguments);}})})(jQuery);
;(function($){$.concat||$.extend({concat:function(){return Array.prototype.concat.apply([],arguments);}})})(jQuery);
$(function() {
var json1 = [{id:1, name: 'xxx'}],
json2 = [{id:2, name: 'xyz'}],
json3 = [{id:3, name: 'xyy'}],
json4 = [{id:4, name: 'xzy'}],
json5 = [{id:5, name: 'zxy'}];
console.log(Array(10).join('-')+'(json1, json2, json3)'+Array(10).join('-'));
console.log($.concat(json1, json2, json3));
console.log(Array(10).join('-')+'(json1, json2, json3, json4, json5)'+Array(10).join('-'));
console.log($.concat(json1, json2, json3, json4, json5));
console.log(Array(10).join('-')+'(json4, json1, json2, json5)'+Array(10).join('-'));
console.log($.concat(json4, json1, json2, json5));
});
center { padding: 3em; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<center>See Console Log</center>
jsFiddle
#3
21
You could try merge
你可以尝试合并
var finalObj = $.merge(json1, json2);
#4
5
Since you are using jQuery. How about the jQuery.extend() method?
因为您使用的是jQuery。jQuery.extend()方法怎么样?
http://api.jquery.com/jQuery.extend/
http://api.jquery.com/jQuery.extend/
Description: Merge the contents of two or more objects together into the first object.
描述:将两个或多个对象的内容合并到第一个对象中。
#5
2
Maybe, you can use the array syntax of javascript :
也许可以使用javascript的数组语法:
var finalObj =[json1 , json2]
#6
2
You can do this using Es 6 new feature :
你可以使用Es 6新功能:
var json1 = [{id:1, name: 'xxx' , ocupation : 'Doctor' }];
var json2 = [{id:2, name: 'xyz' ,ocupation : 'SE'}];
var combineJsonArray = [...json1 , ...json2];
//output should like this [ { id: 1, name: 'xxx', ocupation: 'Doctor' },
{ id: 2, name: 'xyz', ocupation: 'SE' } ]
Or You can put extra string or anything between two json array :
或者可以在两个json数组之间放置额外的字符串或任何内容:
var json3 = [...json1 ,"test", ...json2];
// output should like this : [ { id: 1, name: 'xxx', ocupation: 'Doctor' },
'test',
{ id: 2, name: 'xyz', ocupation: 'SE' } ]
#7
-1
Try the code below, using jQuery extend method:
尝试以下代码,使用jQuery扩展方法:
var json1 = {"name":"ramesh","age":"12"};
var json2 = {"member":"true"};
document.write(JSON.stringify($.extend(true,{},json1,json2)))
#8
-2
var json1=["Chennai","Bangalore"];
var json2=["TamilNadu","Karanataka"];
finaljson=json1.concat(json2);