牛客练习赛7 E 珂朵莉的数列

时间:2023-11-28 13:01:02

珂朵莉的数列

思路:

树状数组+高精度

离散化不知道哪里写错了,一直wa,最后用二分写的离散化

哪位路过大神可以帮我看看原来的那个离散化错在哪里啊

通过代码:

import java.math.BigInteger;
import java.util.*;
import java.util.Scanner; class node
{
int x;
int id;
}
class cmp implements Comparator<node>
{
public int compare(node A,node B)
{
if(A.x<B.x)return -1;
else if(A.x==B.x)return 0;
else return 1;
}
}
public class Main{
public final static int N=(int)1e6+9;
public static int n;
public static int a[]=new int[N];
public static long b[]=new long[N];
public static long bit[]=new long[N];
public static long sum(int x)
{
long ret=0;
while(x>0)
{
ret+=bit[x];
x-=x&(-x);
}
return ret;
}
public static void add(int x,long a)
{
while(x<=n)
{
bit[x]+=a;
x+=x&(-x);
}
}
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
n=reader.nextInt();
for(int i=1;i<=n;i++)
{
a[i]=reader.nextInt();
b[i]=a[i];
}
Arrays.sort(b,1,n+1);
for(int i = 1; i <= n; i++) {
a[i] = Arrays.binarySearch(b, 1 ,n + 1,a[i]);
}
BigInteger ans=BigInteger.valueOf(0);
for(int i=1;i<=n;i++)
{
ans=ans.add(BigInteger.valueOf((sum(n)-sum(a[i]))*(n-i+1)));
add(a[i],i);
}
System.out.println(ans);
}
}

错误代码:

import java.math.BigInteger;
import java.util.*;
import java.util.Scanner; class node
{
int x;
int id;
}
class cmp implements Comparator<node>
{
public int compare(node A,node B)
{
if(A.x<B.x)return -1;
else if(A.x==B.x)return 0;
else return 1;
}
}
public class Main{
public final static int N=(int)1e6+9;
public static int n;
public static node a[]=new node[N];
public static int b[]=new int[N];
public static long bit[]=new long[N];
public static long sum(int x)
{
long ret=0;
while(x>0)
{
ret+=bit[x];
x-=x&(-x);
}
return ret;
}
public static void add(int x,long a)
{
while(x<=n)
{
bit[x]+=a;
x+=x&(-x);
}
}
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
n=reader.nextInt();
for(int i=1;i<=n;i++)
{
a[i]=new node();
a[i].x=reader.nextInt();
a[i].id=i;
}
//
Arrays.sort(a,1,n+1,new cmp()); int cnt=1;
a[0]=new node();
a[0].x=-1;
for(int i=1;i<=n;i++)
{
if(a[i].x!=a[i-1].x)b[a[i].id]=++cnt;
else b[a[i].id]=cnt;
}
//for(int i=1;i<=n;i++)System.out.println(b[i]);
BigInteger ans=BigInteger.valueOf(0);
for(int i=1;i<=n;i++)
{
ans=ans.add(BigInteger.valueOf((sum(cnt)-sum(b[i]))*(n-i+1)));
add(b[i],i);
}
System.out.println(ans);
}
}