从JSON字符串值中删除双引号

I create a JSON string whith dynamical values which looks like this:

我创建一个JSON字符串动态值如下所示:

{"geometry": {"type": "Point", "coordinates": ["78.454", "22.643"]}, "type": "Feature", "properties": {"Number":"123","Plate":"xxx","Position":"xyz",}}

the dynamical values are the coordinates and the values in the properties.

动态值是坐标和性质中的值。

the code to create the string is the following:

创建字符串的代码如下:

var tmpLlrtArr = [];
$.each(data, function(key, value) {
var tmpLlrtObj = {};
            tmpLlrtObj.type = 'Feature';
            tmpLlrtObj.geometry = {};
            tmpLlrtObj.geometry = {};
            tmpLlrtObj.geometry.type = 'Point';
            tmpLlrtObj.geometry.coordinates = [(value.longitude_mdeg * 0.000001).toFixed(6), (value.latitude_mdeg * 0.000001).toFixed(6)];
            tmpLlrtObj.properties = {};
            tmpLlrtObj.properties.Number = value.objectno;
            tmpLlrtObj.properties.Plate = value.objectname;
            tmpLlrtObj.properties.Position = value.postext_short;

            tmpLlrtArr.push(tmpLlrtObj);
});

var llrealTimeJSONString = JSON.stringify(llrealTimeObj);
    console.log(llrealTimeObj);

know I have the problem that, the coordinates are under double quotes and I have no idea how to remove only them.

我有一个问题，坐标在双引号下面，我不知道如何只删除它们。

the possible solutions here on stack overflow doesn't work for me. has anybody an advice for me?

栈溢出的可能解决方案对我不起作用。有人给我提建议吗?

1 个解决方案

#1

Get rid of toFixed(6) to stop converting the numbers to String:

去掉toFixed(6)，停止将数字转换为String:

var tmpLlrtArr = [];
$.each(data, function(key, value) {
var tmpLlrtObj = {};
            tmpLlrtObj.type = 'Feature';
            tmpLlrtObj.geometry = {};
            tmpLlrtObj.geometry = {};
            tmpLlrtObj.geometry.type = 'Point';
            tmpLlrtObj.geometry.coordinates = [(value.longitude_mdeg * 0.000001), (value.latitude_mdeg * 0.000001)];
            tmpLlrtObj.properties = {};
            tmpLlrtObj.properties.Number = value.objectno;
            tmpLlrtObj.properties.Plate = value.objectname;
            tmpLlrtObj.properties.Position = value.postext_short;

            tmpLlrtArr.push(tmpLlrtObj);
});

var llrealTimeJSONString = JSON.stringify(llrealTimeObj);
    console.log(llrealTimeObj);