I had used the following code and i am receiving the firefox firebug error.
我使用了以下代码,我收到firefox firebug错误。
Code:
(canvas anchor)
id:(canvas nextId);
onClick: 'alert("Thank you");';
with:'help me'.
I could load the jqplot libraries in updateRoot SUCCESSFULLY as follows:
我可以在updateRoot SUCCESSFULLY中加载jqplot库,如下所示:
updateRoot: t1
super updateRoot: t1.
t1 javascript resourceUrl:'gemstone/scripts/dist/jquery.min.js'.
t1 javascript resourceUrl:'gemstone/scripts/dist/jquery.jqplot.min.js'.
t1 javascript resourceUrl:'gemstone/scripts/dist/plugins/jqplot.blockRenderer.min.js'.
t1 javascript resourceUrl:'gemstone/scripts/dist/plugins/jqplot.enhancedLegendRenderer.min.js'.
t1 javascript resourceUrl:'gemstone/scripts/dist/plugins/jqplot.bubbleRenderer.min.js'.
t1 javascript resourceUrl:'gemstone/scripts/dist/plugins/jqplot.barRenderer.min.js'.
t1 javascript resourceUrl:'gemstone/scripts/dist/plugins/jqplot.pieRenderer.min.js'.
t1 javascript resourceUrl:'gemstone/scripts/dist/plugins/jqplot.categoryAxisRenderer.min.js'.
t1 javascript resourceUrl:'gemstone/scripts/dist/plugins/jqplot.pointLabels.min.js'.
t1 stylesheet resourceUrl:'gemstone/scripts/dist/jquery.jqplot.min.css'.**.
I am not getting any alert and I am receiving the following javascript error in firebug in firefox.
我没有得到任何警报,我在firefox中的firebug中收到以下javascript错误。
$("#id1").on is not a function
$(“#id1”)。on不是函数
1 个解决方案
#1
1
Remove the '**.' at the end of your #updateRoot: method and see what happens.
除掉 '**。'在#updateRoot:方法的最后,看看会发生什么。
Check the rendered html in the body of the page for your root component. It should be:
检查页面正文中的渲染html以获取根组件。它应该是:
<a id="id1" onclick="alert("Thank you");">help me</a>
Nothing you've shown should change that. If its not then you need to give more information.
你所展示的任何东西都不应该改变它。如果不是那么你需要提供更多信息。
#1
1
Remove the '**.' at the end of your #updateRoot: method and see what happens.
除掉 '**。'在#updateRoot:方法的最后,看看会发生什么。
Check the rendered html in the body of the page for your root component. It should be:
检查页面正文中的渲染html以获取根组件。它应该是:
<a id="id1" onclick="alert("Thank you");">help me</a>
Nothing you've shown should change that. If its not then you need to give more information.
你所展示的任何东西都不应该改变它。如果不是那么你需要提供更多信息。