I need to split a javascript array into n
sized chunks.
我需要将一个javascript数组分割成n个大小的块。
E.g.: Given this array
例如:这个数组
["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"]
and a n
equals to 4, the output should be this:
n等于4,输出应该是这样的
[ ["a1", "a2", "a3", "a4"],
["a5", "a6", "a7", "a8"],
["a9", "a10", "a11", "a12"],
["a13"]
]
I aware of pure javascript solutions for this problem, but since I am already using underscore.js I am wondering if underscore provides a better solution for this.
我知道这个问题的纯javascript解决方案,但是因为我已经在使用下划线了。我想知道下划线是否提供了更好的解决方案。
Edit:
I created a jsPerf test to check how much slower the underscore solution is.
我创建了一个jsPerf测试,以检查下划线解决方案的速度有多慢。
5 个解决方案
#1
84
Take a look at lodash' chunk: https://lodash.com/docs#chunk
看看lodash: https://lodash.com/docs#chunk
var data = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"];
_.chunk(data, 3);
// [
// ["a1", "a2", "a3"],
// ["a4", "a5", "a6"],
// ["a7", "a8", "a9"],
// ["a10", "a11", "a12"],
// ["a13"]
// ]
#2
89
For Underscore based solution try this:
对于基于下划线的解决方案,请尝试以下方法:
var data = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"];
var n = 3;
var lists = _.groupBy(data, function(element, index){
return Math.floor(index/n);
});
lists = _.toArray(lists); //Added this to convert the returned object to an array.
console.log(lists);
Using the chain wrapper method you can combine the two statements as below:
使用链包装方法,您可以将以下两个语句组合在一起:
var data = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"];
var n = 3;
var lists = _.chain(data).groupBy(function(element, index){
return Math.floor(index/n);
}).toArray()
.value();
#3
4
A possibly simpler expression:
可能简单的表达式:
_.range(coll.length / n).map(i => coll.slice(i * n, (i + 1) * n))
#4
0
try this one it is much more practical (for example, if you would want to split the array based on amount of items to be container in each sub array):
试试这个更实用(例如,如果您希望根据每个子数组中要包含的项的数量来分割数组):
function chunk(arr, start, amount){
var result = [],
i,
start = start || 0,
amount = amount || 500,
len = arr.length;
do {
//console.log('appending ', start, '-', start + amount, 'of ', len, '.');
result.push(arr.slice(start, start+amount));
start += amount;
} while (start< len);
return result;
};
and the use in your case:
在你的案例中使用:
var arr = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17],
chunked = chunk(arr, 0, Math.floor(arr.length/3)); //to get 4 nested arrays
console.log(chunked);
and another case:
和另一个案例:
var arr = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17],
chunked = chunk(arr, 0, 3); // to get 6 nested arrays each containing maximum of 3 items
console.log(chunked);
#5
0
Underscore supports _.chunk() natively as of version 1.9.0.
下划线在1.9.0版本中支持_.chunk()。
let data = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"];
_.chunk(data, 4);
// [
// ["a1", "a2", "a3", "a4"],
// ["a5", "a6", "a7", "a8"],
// ["a9", "a10", "a11", "a12"],
// ["a13"]
// ]
#1
84
Take a look at lodash' chunk: https://lodash.com/docs#chunk
看看lodash: https://lodash.com/docs#chunk
var data = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"];
_.chunk(data, 3);
// [
// ["a1", "a2", "a3"],
// ["a4", "a5", "a6"],
// ["a7", "a8", "a9"],
// ["a10", "a11", "a12"],
// ["a13"]
// ]
#2
89
For Underscore based solution try this:
对于基于下划线的解决方案,请尝试以下方法:
var data = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"];
var n = 3;
var lists = _.groupBy(data, function(element, index){
return Math.floor(index/n);
});
lists = _.toArray(lists); //Added this to convert the returned object to an array.
console.log(lists);
Using the chain wrapper method you can combine the two statements as below:
使用链包装方法,您可以将以下两个语句组合在一起:
var data = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"];
var n = 3;
var lists = _.chain(data).groupBy(function(element, index){
return Math.floor(index/n);
}).toArray()
.value();
#3
4
A possibly simpler expression:
可能简单的表达式:
_.range(coll.length / n).map(i => coll.slice(i * n, (i + 1) * n))
#4
0
try this one it is much more practical (for example, if you would want to split the array based on amount of items to be container in each sub array):
试试这个更实用(例如,如果您希望根据每个子数组中要包含的项的数量来分割数组):
function chunk(arr, start, amount){
var result = [],
i,
start = start || 0,
amount = amount || 500,
len = arr.length;
do {
//console.log('appending ', start, '-', start + amount, 'of ', len, '.');
result.push(arr.slice(start, start+amount));
start += amount;
} while (start< len);
return result;
};
and the use in your case:
在你的案例中使用:
var arr = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17],
chunked = chunk(arr, 0, Math.floor(arr.length/3)); //to get 4 nested arrays
console.log(chunked);
and another case:
和另一个案例:
var arr = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17],
chunked = chunk(arr, 0, 3); // to get 6 nested arrays each containing maximum of 3 items
console.log(chunked);
#5
0
Underscore supports _.chunk() natively as of version 1.9.0.
下划线在1.9.0版本中支持_.chunk()。
let data = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "a10", "a11", "a12", "a13"];
_.chunk(data, 4);
// [
// ["a1", "a2", "a3", "a4"],
// ["a5", "a6", "a7", "a8"],
// ["a9", "a10", "a11", "a12"],
// ["a13"]
// ]