大体思路
如果发总金额为 m的 n 个红包,先用一个长度为 n的临时数组 a 存放 n个随机双精度小数 ,然后用 sum表示数组 a 的和,每个红包的金额
代码
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import java.util.Arrays;
import java.util.Random;
import java.math.*;
import java.util.Scanner;
public class Main {
public static long now_time;
public static long seed;
public static int [] get_red_packets( int money, int num) {
Random random = new Random(seed);
seed = random.nextLong();
int [] res = new int [num];
double [] temp= new double [num];
double sum = 0 ;
int sum2 = 0 ;
for ( int i = 0 ; i < num; i++) {
temp[i] = random.nextDouble();
sum += temp[i];
}
for ( int i = 0 ; i < num; i++) {
res[i] = 1 + ( int )(temp[i] / sum * (money-num));
sum2 += res[i]- 1 ;
}
res[random.nextInt(num)]+=money-sum2-num;
return res;
}
public static void show( int [] red_packet){
System.out.println( "红包 : " + Arrays.toString(red_packet));
}
public static void main(String[] args) {
int num, money;
Scanner scanner = new Scanner(System.in);
now_time = System.currentTimeMillis();
Random init_random = new Random(now_time);
seed = init_random.nextLong();
System.out.println( "请输入要分发的红包数量:" );
num = scanner.nextInt();
System.out.println( "请输入要分发的红包总金额(分):" );
money = scanner.nextInt();
int a[] = get_red_packets(money,num);
show(a);
}
}
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原文链接:https://blog.csdn.net/Evrse/article/details/110144412