I want to do the following - Allow users to input a physical address in ios app. - This address is converted to longitude/latitude - Django server code checks to see nearby locations.
我想执行以下操作 - 允许用户在ios应用程序中输入物理地址。 - 此地址转换为经度/纬度 - Django服务器代码检查以查看附近的位置。
How can I do this most efficiently?
我怎样才能最有效地完成这项工作?
Should I convert the address to longitude and latitude in ios app and then send the coordinates to django server code, or should I send the address to django server code and then covert address to longitude and latitude?
我应该在ios app中将地址转换为经度和纬度,然后将坐标发送到django服务器代码,还是应该将地址发送到django服务器代码然后将地址转换为经度和纬度?
any help would be appreciated!
任何帮助,将不胜感激!
3 个解决方案
#1
5
According to the Apple's Location Awareness Programming Guide You can achieve this using a CLGeocoder object:
根据Apple的位置感知编程指南您可以使用CLGeocoder对象实现此目的:
CLGeocoder* geocoder = [[CLGeocoder alloc] init];
[geocoder geocodeAddressString:@"Your Address"
completionHandler:^(NSArray* placemarks, NSError* error){
for (CLPlacemark* aPlacemark in placemarks)
{
// Process the placemark.
}
}];
A CLPlacemark object has a property called location that yields latitude and longitude for the place.
CLPlacemark对象具有一个名为location的属性,可以为该位置生成纬度和经度。
#2
1
You can use this function to get (latitude, longitude)
tuple on the django side
您可以使用此功能获取django侧的(纬度,经度)元组
import urllib, urllib2
import simplejson as json
def getLatLng( address ):
""" Native address format is House Number, Street Direction, Street Name,
Street Suffix, City, State, Zip, Country """
TIMEOUT = 3
try:
url = "http://maps.google.com/maps/api/geocode/json?address=" + urllib.quote_plus( address.encode('utf-8') ) + "&sensor=false"
opener = urllib2.build_opener()
req = urllib2.Request( url )
data = json.load( opener.open(req, None, TIMEOUT) )
results = data['results']
if len( results ):
location = results[0]['geometry']['location']
return ( location['lat'], location['lng'] )
else:
return None
except:
return None
#3
0
Use the below link,this will return json which consist of latitude and longitude for the physical address.
使用下面的链接,这将返回包含物理地址的纬度和经度的json。
http://maps.google.com/maps/api/geocode/json?address=Newyork&sensor=false
#1
5
According to the Apple's Location Awareness Programming Guide You can achieve this using a CLGeocoder object:
根据Apple的位置感知编程指南您可以使用CLGeocoder对象实现此目的:
CLGeocoder* geocoder = [[CLGeocoder alloc] init];
[geocoder geocodeAddressString:@"Your Address"
completionHandler:^(NSArray* placemarks, NSError* error){
for (CLPlacemark* aPlacemark in placemarks)
{
// Process the placemark.
}
}];
A CLPlacemark object has a property called location that yields latitude and longitude for the place.
CLPlacemark对象具有一个名为location的属性,可以为该位置生成纬度和经度。
#2
1
You can use this function to get (latitude, longitude)
tuple on the django side
您可以使用此功能获取django侧的(纬度,经度)元组
import urllib, urllib2
import simplejson as json
def getLatLng( address ):
""" Native address format is House Number, Street Direction, Street Name,
Street Suffix, City, State, Zip, Country """
TIMEOUT = 3
try:
url = "http://maps.google.com/maps/api/geocode/json?address=" + urllib.quote_plus( address.encode('utf-8') ) + "&sensor=false"
opener = urllib2.build_opener()
req = urllib2.Request( url )
data = json.load( opener.open(req, None, TIMEOUT) )
results = data['results']
if len( results ):
location = results[0]['geometry']['location']
return ( location['lat'], location['lng'] )
else:
return None
except:
return None
#3
0
Use the below link,this will return json which consist of latitude and longitude for the physical address.
使用下面的链接,这将返回包含物理地址的纬度和经度的json。
http://maps.google.com/maps/api/geocode/json?address=Newyork&sensor=false