如何使用节点glob获取第一个X文件

Using node-glob, is it possible to specify a pattern that will return only the first X matching files, rather than all matches?

使用node-glob，是否可以指定仅返回前X个匹配文件的模式，而不是所有匹配？

For example, if I wanted all JavaScript files, my pattern would be **/*.js. But what if I only wanted the first 5 JavaScript files?

例如，如果我想要所有JavaScript文件，我的模式将是** / * .js。但是，如果我只想要前5个JavaScript文件呢？

I realize that there are other options, such as I could take the resulting fileset array and slice it. The underlying case here makes that difficult, so I am trying to accomplish this directly from the glob pattern.

我意识到还有其他选项，例如我可以获取生成的文件集数组并对其进行切片。这里的基础案例很难，所以我试图直接从glob模式完成这个。

1 个解决方案

#1

You can create your own Glob object like this:

您可以像这样创建自己的Glob对象：

var i = 0;
var Glob = require("glob").Glob;
var mg = new Glob(pattern, options, cb);
mg.on("match", function(matched) {
    console.log(matched);
    i++;
    if(i == 5) mg.abort();
});

It is an event emitter so you can listen for match event which will be fired when a file is found. With each match increase the counter and if it has reached your threshold you can call mg.abort() to stop the search.

它是一个事件发射器，因此您可以侦听匹配事件，该事件将在找到文件时触发。每次匹配都会增加计数器，如果达到阈值，您可以调用mg.abort（）来停止搜索。