如何禁用UISwitch?

Is this possible to disable a UISwitch? I do not mean putting it in an OFF state, I mean disabling user interaction, and having it appear gray.

可以禁用UISwitch吗?我不是说把它放在关闭状态，我是说禁用用户交互，让它显示为灰色。

In my app I have two conditions

在我的应用中有两个条件

if (condition == true) {  
  // UISwitch should be enabled  
} else {  
  // UISwitch should be visible, but disabled  
  // e.g uiswitch.enable=NO;  
}

Any suggestions?

有什么建议吗?

4 个解决方案

#1

This should do it:

这应该这样做:

switch.enabled = NO;

or equivalently:

或者说:

[switch setEnabled:NO];

where switch is whatever your UISwitch variable name is.

这里的switch是UISwitch变量的名称。

Edit 18-Apr-2018

编辑18 - 4月- 2018

The answer above is (clearly) an Objective-C solution, written well before anyone had ever heard of Swift. The Swift equivalent solution is, of course:

上面的答案(很明显)是一个Objective-C的解决方案，在任何人听说Swift之前就已经写好了。当然，Swift等价的解决方案是:

switch.isEnabled = false

开关。isEnabled = false

#2

Yes you can. UISwitch inherits from UIControl, and UIControl has an enabled property. Apple's UIControl Documentation has all of the details.

是的,你可以。UISwitch继承自UIControl, UIControl有一个enabled属性。苹果的UIControl文档有所有的细节。

To enable

要启用

switch.enabled = YES;

To disable

禁用

switch.enabled = NO;

#3

For those looking for Swift 3,

对于那些寻找Swift 3的人，

switch.isEnabled = false // Disabled switch

I know you didn't ask for "off" state, but just in case anybody, like myself, stumbled upon here :

我知道你并没有要求“关闭”状态，但万一有人，像我一样，在这里偶然发现:

switch.isOn = false

#4

-6

[switchName enabled] = NO;

[switchName启用]=没有;

Use that to disable your switch.

使用它来禁用你的开关。

EDIT thanks to rckoenes: "You should not try to set a property via getter. You should use either the setter of . syntax property."

感谢rckoenes:“您不应该尝试通过getter来设置属性。你应该使用。语法属性。”

#1