如何在gcc中禁用尾调优化

Wondering if anyone knows the flag for gcc to disable tailcall optimizations. Basically in a tailcall optimization, gcc will replace a stack frame when the return value from a called function is passed through (via return) or nothing else happens in the function.

想知道是否有人知道gcc禁用尾调优化的标志。基本上在尾调用优化中,当被调用函数的返回值通过(通过返回)或函数中没有其他任何内容发生时,gcc将替换堆栈帧。

That is, in

也就是说,在

 void main() {
     foo();
 }

 void foo() {
     bar();
 }

 void bar() {
     /* at this point in code, the foo() stack frame no longer exists! */    
 }

When foo calls bar, gcc emits code that replaces the stack frame for foo, rather than adding a new stack frame.

当foo调用bar时,gcc会发出代替foo的堆栈帧的代码,而不是添加新的堆栈帧。

My company has a stack unwinder that can print out a stack trace from any point in code. tailcall optimization makes stack frames disappear, which can confuse the stack trace somewhat.

我公司有一个堆栈展开器,可以从代码中的任何一点打印出堆栈跟踪。 tailcall优化使堆栈帧消失,这可能会在一定程度上混淆堆栈跟踪。

I am compiling for x86-64 using gcc4.3.

我正在使用gcc4.3编译x86-64。

Thanks in advance! P

提前致谢! P

2 个解决方案

#1

GCC manual:

   -foptimize-sibling-calls
       Optimize sibling and tail recursive calls.

       Enabled at levels -O2, -O3, -Os.

So either compile with -O0/-O1, or use -fno-optimize-sibling-calls.

因此要么使用-O0 / -O1进行编译,要么使用-fno-optimize-sibling-calls。

#2

Untested: -fno-optimize-sibling-calls

http://gcc.gnu.org/onlinedocs/gcc/Optimize-Options.html

#1