I'm having a problem unit testing the following method:
我有一个问题单元测试以下方法:
$scope.changeLocation = function (url) {
$location.path(url).search({ ref: "outline" });
};
I've written the following unit test that currently fails with this error (TypeError: Cannot read property 'search' of undefined):
我编写了以下单元测试,该测试当前因此错误而失败(TypeError:无法读取未定义的属性'search'):
var $locationMock = { path: function () { }, search: function () { } };
it('changeLocation should update location correctly', function () {
$controllerConstructor('CourseOutlineCtrl', { $scope: $scope, $location: $locationMock });
var url = "/url/";
spyOn($locationMock, "path");
spyOn($locationMock, "search");
$scope.changeLocation(url);
expect($locationMock.search).toHaveBeenCalledWith({ ref: "outline" });
expect($locationMock.path).toHaveBeenCalledWith(url);
});
If I change my function to the following, the test passes:
如果我将我的功能更改为以下内容,则测试通过:
$scope.changeLocation = function (url) {
$location.path(url);
$location.search({ ref: "outline" });
};
How do I unit test this method when I'm using method chaining? Do I need to setup my $locationMock differently? For the life of me I cannot figure this out.
当我使用方法链时,如何对此方法进行单元测试?我需要以不同方式设置$ locationMock吗?对于我的生活,我无法弄清楚这一点。
2 个解决方案
#1
20
That is because your mock does not return location object to be able to chain through. Using Jasmine 2.0 you can change your mock to:
那是因为你的mock不会返回位置对象以便能够链接。使用Jasmine 2.0,您可以将模拟更改为:
var $locationMock = { path: function () { return $locationMock; },
search: function () { return $locationMock; } };
and
和
spyOn($locationMock, "path").and.callThrough();
spyOn($locationMock, "search").and.callThrough(); //if you are chaining from search
or add:
或添加:
spyOn($locationMock, "path").and.returnValue($locationMock);
spyOn($locationMock, "search").and.returnValue($locationMock); //if you are chaining from search
Or just create a spy object (less code):
或者只是创建一个间谍对象(更少的代码):
var $locationMock = jasmine.createSpyObj('locationMock', ['path', 'search']);
and
和
$locationMock.path.and.returnValue($locationMock);
$locationMock.search.and.returnValue($locationMock); //if you are chaining from search
#2
0
try :
尝试:
spyOn($locationMock, "path").and.callThrough();
Else you'r calling search on a mock not $location
否则你会在模拟非$位置上调用搜索
#1
20
That is because your mock does not return location object to be able to chain through. Using Jasmine 2.0 you can change your mock to:
那是因为你的mock不会返回位置对象以便能够链接。使用Jasmine 2.0,您可以将模拟更改为:
var $locationMock = { path: function () { return $locationMock; },
search: function () { return $locationMock; } };
and
和
spyOn($locationMock, "path").and.callThrough();
spyOn($locationMock, "search").and.callThrough(); //if you are chaining from search
or add:
或添加:
spyOn($locationMock, "path").and.returnValue($locationMock);
spyOn($locationMock, "search").and.returnValue($locationMock); //if you are chaining from search
Or just create a spy object (less code):
或者只是创建一个间谍对象(更少的代码):
var $locationMock = jasmine.createSpyObj('locationMock', ['path', 'search']);
and
和
$locationMock.path.and.returnValue($locationMock);
$locationMock.search.and.returnValue($locationMock); //if you are chaining from search
#2
0
try :
尝试:
spyOn($locationMock, "path").and.callThrough();
Else you'r calling search on a mock not $location
否则你会在模拟非$位置上调用搜索