I'm having trouble with query parameters in socket.io.
我在socket.io中遇到查询参数问题。
Server Side:
var io = require('socket.io')(server);
io.of('/1').on('connection', function(socket){
console.log(socket.request._query['test']);
});
io.of('/2').on('connection', function(socket){
console.log(socket.request._query['test']);
});
io.of('/3').on('connection', function(socket){
console.log(socket.request._query['test']);
});
Client side:
io('/1', {
query: 'test=1'
});
io('/2', {
query: 'test=2'
});
io('/3', {
query: 'test=3'
});
Prints:
1
1
1
Instead of:
1
2
3
The rest is just a default express scaffold.
其余的只是一个默认的快速脚手架。
Why is the query parameter always 1?
为什么查询参数总是1?
Thanks.
1 个解决方案
#1
0
io('/1', {
query: 'test=1',
multiplex: false
});
io('/2', {
query: 'test=2',
multiplex: false
});
io('/3', {
query: 'test=3',
multiplex: false
});
Does the trick. See https://github.com/socketio/socket.io/issues/2632
诀窍。请参阅https://github.com/socketio/socket.io/issues/2632
#1
0
io('/1', {
query: 'test=1',
multiplex: false
});
io('/2', {
query: 'test=2',
multiplex: false
});
io('/3', {
query: 'test=3',
multiplex: false
});
Does the trick. See https://github.com/socketio/socket.io/issues/2632
诀窍。请参阅https://github.com/socketio/socket.io/issues/2632