python 的 zipfile 提供了非常便捷的方法来压缩和解压 zip 文件。
例如,在py脚本所在目录中,有如下文件:
1
2
3
4
5
|
readability/readability.js
readability/readability.txt
readability/readability-print.css
readability/sprite-readability.png
readability/readability.css
|
将 readability 目录中的文件压缩到脚本所在目录的 readability.zip 文件中,保持相同的文件结构,然后打印出生成的压缩包 的文件列表,再用两种方式分别解压文件到脚本所在目录的 output 目录和 output/bak 目录中。
脚本如下:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
|
#!/usr/vin/env python
# coding: utf-8
"""
压缩和解压zip文件
"""
import os
import zipfile
def compress(zip_file, input_dir):
f_zip = zipfile.ZipFile(zip_file, 'w' )
for root, dirs, files in os.walk(input_dir):
for f in files:
# 获取文件相对路径,在压缩包内建立相同的目录结构
abs_path = os.path.join(os.path.join(root, f))
rel_path = os.path.relpath(abs_path, os.path.dirname(input_dir))
f_zip.write(abs_path, rel_path, zipfile.ZIP_STORED)
def extract(zip_file, output_dir):
f_zip = zipfile.ZipFile(zip_file, 'r' )
# 解压所有文件到指定目录
f_zip.extractall(output_dir)
# 逐个解压文件到指定目录
for f in f_zip.namelist():
f_zip.extract(f, os.path.join(output_dir, 'bak' ))
def printdir(zip_file):
f_zip = zipfile.ZipFile(zip_file, 'r' )
print '== printdir() ============================'
f_zip.printdir()
print
print '== namelist() ============================'
for f in f_zip.namelist():
print f
if __name__ = = '__main__' :
zip_file = 'readability.zip'
compress(zip_file, os.path.join(os.getcwd(), 'readability' ))
printdirzip_file)
extract(zip_file, 'output' )< / pre>
|
python暴力破解含密码的zip压缩文件
思路:
1.先自己生成一份txt的密码字典
2.然后读取出来,一个个的尝试,当密码错误是,程序会报错中断,所以密码错误,要使用pass
3.当解压缩成功后,中断程序,输出正确密码
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
|
import zipfile
import os
from threading import Thread
import time
#压缩文件的路径
path = r 'C:\Users\Administrator\Desktop\moeMaid-master.zip'
#password='1234'
def pojie_zip(path,password):
if path[ - 4 :] = = '.zip' :
#path = dir+ '\\' +file
#print path
zip = zipfile.ZipFile(path, "r" ,zipfile.zlib.DEFLATED)
#print zip.namelist()
try :
#若解压成功,则返回True,和密码
zip .extractall(path = 'C:\\Users\\Administrator\\Desktop\\' ,members = zip .namelist() , pwd = password)
print ' ----success!,The password is %s' % password
zip .close()
return True
except :
pass #如果发生异常,不报错
print 'error'
def get_pass():
#密码字典的路径
passPath = 'C:\\Users\\Administrator\\Desktop\\zip.txt'
passFile = open (passPath, 'r' )
for line in passFile.readlines():
password = line.strip( '\n' )
print 'Try the password %s' % password
if pojie_zip(path,password):
break
passFile.close()
if __name__ = = '__main__' :
start = time.clock()
get_pass()
print "done (%.2f seconds)" % (time.clock() - start)
|
这是我解压缩一个5.4M文件的速度,其实时间都花在了解压缩上了