My current array: abc = ['a', 'b', 'c', 'd'];
我目前的数组:abc = ['a','b','c','d'];
I understand .pop()
remove and returns the last item of an array, thus: abc.pop(); = 'd'
我理解.pop()删除并返回数组的最后一项,因此:abc.pop(); ='d'
However, I want to remove the last item, and return the array. So it would return:
但是,我想删除最后一项,并返回该数组。所以会回来:
['a', 'b', 'c'];
['a','b','c'];
Is there a JavaScript function for this?
这有JavaScript功能吗?
5 个解决方案
#1
3
pop()
function also removes last element from array, so this is what you want(Demo on JSFiddle):
pop()函数也从数组中删除最后一个元素,所以这就是你想要的(在JSFiddle上演示):
var abc = ['a', 'b', 'c', 'd'];
abc.pop()
alert(abc); // a, b, c
#2
2
Array.prototype.popAndReturnArray = function( ){
this.pop();
return this;
}
#3
2
in an expression, using the comma operator.
( documentation:https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Comma_Operator // thx @Zero )
在表达式中,使用逗号运算符。 (文档:https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Comma_Operator // thx @Zero)
(abc.length--, abc)
// expl :
(abc.length--, abc).sort();
Or in a function, most handy being to set it on Array prototype :
或者在函数中,最方便的是将它设置在Array原型上:
Array.prototype.removeLast = function () {
this.length--;
return this;
}
called with
打电话给
var abc = ['you', 'and', 'me'];
abc.removeLast();
which you can daisy chain :
你可以菊花链:
abc.removeLast().sort();
#4
1
Do this
做这个
abc = abc.splice(0, abc.length-1)
Edit: It has been pointed out that this actually returns a new array(albeit with the same variable name).
编辑:已经指出这实际上返回一个新数组(尽管具有相同的变量名)。
If you want to return the same array, you'll have to make your own function
如果要返回相同的数组,则必须自己创建函数
function popper(arr) {
arr.pop();
return arr;
}
#5
0
Yes, what you want is more generally the "filter" function.
是的,你想要的更通常是“过滤”功能。
It takes a function and returns everything that passes a test function, here's an example:
它需要一个函数并返回通过测试函数的所有内容,这是一个例子:
abc = ['a', 'b', 'c', 'd'];
abc.filter(function(member,index) { return index !== abc.length - 1; });
#1
3
pop()
function also removes last element from array, so this is what you want(Demo on JSFiddle):
pop()函数也从数组中删除最后一个元素,所以这就是你想要的(在JSFiddle上演示):
var abc = ['a', 'b', 'c', 'd'];
abc.pop()
alert(abc); // a, b, c
#2
2
Array.prototype.popAndReturnArray = function( ){
this.pop();
return this;
}
#3
2
in an expression, using the comma operator.
( documentation:https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Comma_Operator // thx @Zero )
在表达式中,使用逗号运算符。 (文档:https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Comma_Operator // thx @Zero)
(abc.length--, abc)
// expl :
(abc.length--, abc).sort();
Or in a function, most handy being to set it on Array prototype :
或者在函数中,最方便的是将它设置在Array原型上:
Array.prototype.removeLast = function () {
this.length--;
return this;
}
called with
打电话给
var abc = ['you', 'and', 'me'];
abc.removeLast();
which you can daisy chain :
你可以菊花链:
abc.removeLast().sort();
#4
1
Do this
做这个
abc = abc.splice(0, abc.length-1)
Edit: It has been pointed out that this actually returns a new array(albeit with the same variable name).
编辑:已经指出这实际上返回一个新数组(尽管具有相同的变量名)。
If you want to return the same array, you'll have to make your own function
如果要返回相同的数组,则必须自己创建函数
function popper(arr) {
arr.pop();
return arr;
}
#5
0
Yes, what you want is more generally the "filter" function.
是的,你想要的更通常是“过滤”功能。
It takes a function and returns everything that passes a test function, here's an example:
它需要一个函数并返回通过测试函数的所有内容,这是一个例子:
abc = ['a', 'b', 'c', 'd'];
abc.filter(function(member,index) { return index !== abc.length - 1; });