本文实例讲述了python比较2个xml内容的方法。分享给大家供大家参考。具体分析如下:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
|
from xml.etree import ElementTree
OK = True
main_pid = 10000
loop_depth = 0
def compare_xml(left, right, key_info = '.' ):
global loop_depth
loop_depth + = 1
if loop_depth = = 1 : print
if left.tag ! = right.tag:
print_diff(main_pid, key_info, 'difftag' , left.tag, right.tag)
return
if left.text ! = right.text:
print_diff(main_pid, key_info, 'difftext' , left.text, right.text)
return
leftitems = dict (left.items())
rightitems = dict (right.items())
for k,v in leftitems.items():
if k not in rightitems:
s = '%s/%s' % (key_info, left.tag)
print_diff(main_pid, s, 'lostattr' , k, "")
for k,v in rightitems.items():
if k not in leftitems:
s = '%s/%s' % (key_info, right.tag)
print_diff(main_pid, s, 'extraattr' , "", k)
leftnodes = left.getchildren()
rightnodes = right.getchildren()
leftlen = len (leftnodes)
rightlen = len (rightnodes)
if leftlen ! = rightlen:
s = '%s/%s' % (key_info, right.tag)
print_diff(main_pid, s, 'difflen' , leftlen, rightlen)
return
l = leftlen<rightlen and leftlen or rightlen
d = {}
for i in xrange (l):
node = leftnodes[i]
if node.tag not in d:
d[node.tag] = 1
tag = node.tag
else :
tag = node.tag + str (d[node.tag])
d[node.tag] + = 1
s = '%s/%s' % (key_info, tag)
compare_xml(leftnodes[i], rightnodes[i], s)
def print_diff(main_pid, key_info, msg, base_type, test_type):
global OK
info = u '[ %-5s ] %s -> %-40s [ %s != %s ]' % (msg.upper(), main_pid, key_info.strip( './' ), base_type, test_type)
print info.encode( 'gbk' )
OK = False
|
调用:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
|
if __name__ = = '__main__' :
s1 = '''''<?xml version="1.0" encoding="UTF-8"?> \
<employees> \
<employee id = '1'> \
<name>linux</name>\
<age>30</age>\
</employee>\
<employee id = '2'> \
<name>windows</name>\
<age>20</age>\
</employee>\
</employees>'''
s2 = '''''<?xml version="1.0" encoding="UTF-8"?> \
<employees> \
<employee id = '3'> \
<name>windows</name>\
<age>20</age>\
</employee>\
<employee id = '4'> \
<name>linux</name>\
<age>30</age>\
</employee>\
</employees>'''
lroot = ElementTree.fromstring(s1)
rroot = ElementTree.fromstring(s2)
compare_xml(lroot, rroot)
|
希望本文所述对大家的Python程序设计有所帮助。