本文实例讲述了PHP实现单链表翻转操作。分享给大家供大家参考,具体如下:
当一个序列中只含有指向它的后继结点的链接时,就称该链表为单链表。
这里给出了一个单链表的定义及翻转操作方法:
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<?php
/**
* @file reverseLink.php
* @author showersun
* @date 2016/03/01 10:33:25
**/
class Node{
private $value ;
private $next ;
public function __construct( $value =null){
$this ->value = $value ;
}
public function getValue(){
return $this ->value;
}
public function setValue( $value ){
$this ->value = $value ;
}
public function getNext(){
return $this ->next;
}
public function setNext( $next ){
$this ->next = $next ;
}
}
//遍历,将当前节点的下一个节点缓存后更改当前节点指针
function reverse( $head ){
if ( $head == null){
return $head ;
}
$pre = $head ; //注意:对象的赋值
$cur = $head ->getNext();
$next = null;
while ( $cur != null){
$next = $cur ->getNext();
$cur ->setNext( $pre );
$pre = $cur ;
$cur = $next ;
}
//将原链表的头节点的下一个节点置为null,再将反转后的头节点赋给head
$head ->setNext(null);
$head = $pre ;
return $head ;
}
//递归,在反转当前节点之前先反转后续节点
function reverse2( $head ){
if (null == $head || null == $head ->getNext()) {
return $head ;
}
$reversedHead = reverse2( $head ->getNext());
$head ->getNext()->setNext( $head );
$head ->setNext(null);
return $reversedHead ;
}
function test(){
$head = new Node(0);
$tmp = null;
$cur = null;
// 构造一个长度为10的链表,保存头节点对象head
for ( $i =1; $i <10; $i ++){
$tmp = new Node( $i );
if ( $i == 1){
$head ->setNext( $tmp );
} else {
$cur ->setNext( $tmp );
}
$cur = $tmp ;
}
//print_r($head);exit;
$tmpHead = $head ;
while ( $tmpHead != null){
echo $tmpHead ->getValue(). ' ' ;
$tmpHead = $tmpHead ->getNext();
}
echo "\n" ;
//$head = reverse($head);
$head = reverse2( $head );
while ( $head != null){
echo $head ->getValue(). ' ' ;
$head = $head ->getNext();
}
}
test();
?>
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运行结果:
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0 1 2 3 4 5 6 7 8 9 9 8 7 6 5 4 3 2 1 0
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希望本文所述对大家PHP程序设计有所帮助。
原文链接:http://blog.csdn.net/u013474436/article/details/50773736