WinForm实现状态栏跑马灯效果的方法示例

时间:2022-04-13 08:24:48

本文实例讲述了WinForm实现状态栏跑马灯效果的方法。分享给大家供大家参考,具体如下:

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using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace WindowsFormsApplication1
{
  public partial class Form1 : Form
  {
    public Form1()
    {
      InitializeComponent();
    }
    private Label label = new Label();
    public string text = "csdn baihe_591";
    private void Form1_Load(object sender, EventArgs e)
    {
      this.label.Location = new Point(149, 13);
      this.label.Size = new Size(134, 16);
      this.Controls.Add(label);
      this.label.Text = "";
      this.timer1.Enabled = true;
      this.timer1.Interval = 500;
      p = new PointF(this.label.Size.Width, 0);
    }
    PointF p;
    Font f = new Font("宋体", 10);
    Color c = Color.White;
    string temp;
    private void timer1_Tick(object sender, EventArgs e)
    {
      Graphics g = this.label.CreateGraphics();
      SizeF s = new SizeF();
      s = g.MeasureString(text, f);//测量文字长度
      Brush brush = Brushes.Black;
      g.Clear(c);//清除背景
      if (temp != text)//文字改变时,重新显示
      {
        p = new PointF(this.label.Size.Width, 0);
        temp = text;
      }
      else
        p = new PointF(p.X - 10, 0);//每次偏移10
      if (p.X <= -s.Width)
        p = new PointF(this.label.Size.Width, 0);
      g.DrawString(text, f, brush, p);
    }
  }
}

希望本文所述对大家C#程序设计有所帮助。