I want to show the location of an address in Google Maps.
我想在Google地图中显示地址的位置。
How do I get the latitude and longitude of an address using the Google Maps API?
如何使用Google Maps API获取地址的纬度和经度?
7 个解决方案
#1
119
public GeoPoint getLocationFromAddress(String strAddress){
Geocoder coder = new Geocoder(this);
List<Address> address;
GeoPoint p1 = null;
try {
address = coder.getFromLocationName(strAddress,5);
if (address==null) {
return null;
}
Address location=address.get(0);
location.getLatitude();
location.getLongitude();
p1 = new GeoPoint((double) (location.getLatitude() * 1E6),
(double) (location.getLongitude() * 1E6));
return p1;
}
}
strAddress
is a string containing the address. The address
variable holds the converted addresses.
strAddress是包含地址的字符串。地址变量保存转换后的地址。
#2
58
Ud_an's solution with updated API's
Ud_an的解决方案包含更新的API
Note: LatLng class is part of Google Play Services.
注意:LatLng类是Google Play服务的一部分。
Mandatory:
强制性:
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>
<uses-permission android:name="android.permission.INTERNET"/>
Update: If you have target SDK 23 and above, make sure you take care of runtime permission for location.
更新:如果您有目标SDK 23及更高版本,请确保您负责位置的运行时权限。
public LatLng getLocationFromAddress(Context context,String strAddress) {
Geocoder coder = new Geocoder(context);
List<Address> address;
LatLng p1 = null;
try {
// May throw an IOException
address = coder.getFromLocationName(strAddress, 5);
if (address == null) {
return null;
}
Address location = address.get(0);
p1 = new LatLng(location.getLatitude(), location.getLongitude() );
} catch (IOException ex) {
ex.printStackTrace();
}
return p1;
}
#3
51
If you want to place your address in google map then easy way to use following
如果您想将地址放在谷歌地图中,那么可以轻松使用以下内容
Intent searchAddress = new Intent(Intent.ACTION_VIEW,Uri.parse("geo:0,0?q="+address));
startActivity(searchAddress);
OR
要么
if you needed to get lat long from your address then use Google Place Api following
如果您需要从您的地址获得很长的时间,请使用Google Place Api
create a method that returns a JSONObject with the response of the HTTP Call like following
创建一个方法,返回带有HTTP调用响应的JSONObject,如下所示
public static JSONObject getLocationInfo(String address) {
StringBuilder stringBuilder = new StringBuilder();
try {
address = address.replaceAll(" ","%20");
HttpPost httppost = new HttpPost("http://maps.google.com/maps/api/geocode/json?address=" + address + "&sensor=false");
HttpClient client = new DefaultHttpClient();
HttpResponse response;
stringBuilder = new StringBuilder();
response = client.execute(httppost);
HttpEntity entity = response.getEntity();
InputStream stream = entity.getContent();
int b;
while ((b = stream.read()) != -1) {
stringBuilder.append((char) b);
}
} catch (ClientProtocolException e) {
} catch (IOException e) {
}
JSONObject jsonObject = new JSONObject();
try {
jsonObject = new JSONObject(stringBuilder.toString());
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return jsonObject;
}
now pass that JSONObject to getLatLong() method like following
现在将JSONObject传递给getLatLong()方法,如下所示
public static boolean getLatLong(JSONObject jsonObject) {
try {
longitute = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lng");
latitude = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lat");
} catch (JSONException e) {
return false;
}
return true;
}
I hope this helps to you nd others..!! Thank you..!!
我希望这对你和其他人有帮助.. !!谢谢..!!
#4
6
The following code will work for google apiv2:
以下代码适用于google apiv2:
public void convertAddress() {
if (address != null && !address.isEmpty()) {
try {
List<Address> addressList = geoCoder.getFromLocationName(address, 1);
if (addressList != null && addressList.size() > 0) {
double lat = addressList.get(0).getLatitude();
double lng = addressList.get(0).getLongitude();
}
} catch (Exception e) {
e.printStackTrace();
} // end catch
} // end if
} // end convertAddress
Where address is the String (123 Testing Rd City State zip) you want to convert to LatLng.
其中address是要转换为LatLng的String(123 Testing Rd City State zip)。
#5
3
This is how you can find the latitude and longitude of where we have click on map.
这是您可以找到我们点击地图的纬度和经度的方法。
public boolean onTouchEvent(MotionEvent event, MapView mapView)
{
//---when user lifts his finger---
if (event.getAction() == 1)
{
GeoPoint p = mapView.getProjection().fromPixels(
(int) event.getX(),
(int) event.getY());
Toast.makeText(getBaseContext(),
p.getLatitudeE6() / 1E6 + "," +
p.getLongitudeE6() /1E6 ,
Toast.LENGTH_SHORT).show();
}
return false;
}
it works well.
它运作良好。
To get the location's address we can use geocoder class.
要获取位置的地址,我们可以使用地理编码器类。
#6
1
An answer to Kandha problem above :
以上Kandha问题的答案:
It throws the "java.io.IOException service not available" i already gave those permission and include the library...i can get map view...it throws that IOException at geocoder...
它抛出“java.io.IOException服务不可用”我已经给了这些权限并包含了库...我可以获得地图视图...它会在地理编码器处抛出IOException ...
I just added a catch IOException after the try and it solved the problem
我在尝试后添加了一个catch IOException,它解决了问题
catch(IOException ioEx){
return null;
}
#7
0
Geocoder coder = new Geocoder(this);
List<Address> addresses;
try {
addresses = coder.getFromLocationName(address, 5);
if (addresses == null) {
}
Address location = addresses.get(0);
double lat = location.getLatitude();
double lng = location.getLongitude();
Log.i("Lat",""+lat);
Log.i("Lng",""+lng);
LatLng latLng = new LatLng(lat,lng);
MarkerOptions markerOptions = new MarkerOptions();
markerOptions.position(latLng);
googleMap.addMarker(markerOptions);
googleMap.animateCamera(CameraUpdateFactory.newLatLngZoom(latLng,12));
} catch (IOException e) {
e.printStackTrace();
}
#1
119
public GeoPoint getLocationFromAddress(String strAddress){
Geocoder coder = new Geocoder(this);
List<Address> address;
GeoPoint p1 = null;
try {
address = coder.getFromLocationName(strAddress,5);
if (address==null) {
return null;
}
Address location=address.get(0);
location.getLatitude();
location.getLongitude();
p1 = new GeoPoint((double) (location.getLatitude() * 1E6),
(double) (location.getLongitude() * 1E6));
return p1;
}
}
strAddress
is a string containing the address. The address
variable holds the converted addresses.
strAddress是包含地址的字符串。地址变量保存转换后的地址。
#2
58
Ud_an's solution with updated API's
Ud_an的解决方案包含更新的API
Note: LatLng class is part of Google Play Services.
注意:LatLng类是Google Play服务的一部分。
Mandatory:
强制性:
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>
<uses-permission android:name="android.permission.INTERNET"/>
Update: If you have target SDK 23 and above, make sure you take care of runtime permission for location.
更新:如果您有目标SDK 23及更高版本,请确保您负责位置的运行时权限。
public LatLng getLocationFromAddress(Context context,String strAddress) {
Geocoder coder = new Geocoder(context);
List<Address> address;
LatLng p1 = null;
try {
// May throw an IOException
address = coder.getFromLocationName(strAddress, 5);
if (address == null) {
return null;
}
Address location = address.get(0);
p1 = new LatLng(location.getLatitude(), location.getLongitude() );
} catch (IOException ex) {
ex.printStackTrace();
}
return p1;
}
#3
51
If you want to place your address in google map then easy way to use following
如果您想将地址放在谷歌地图中,那么可以轻松使用以下内容
Intent searchAddress = new Intent(Intent.ACTION_VIEW,Uri.parse("geo:0,0?q="+address));
startActivity(searchAddress);
OR
要么
if you needed to get lat long from your address then use Google Place Api following
如果您需要从您的地址获得很长的时间,请使用Google Place Api
create a method that returns a JSONObject with the response of the HTTP Call like following
创建一个方法,返回带有HTTP调用响应的JSONObject,如下所示
public static JSONObject getLocationInfo(String address) {
StringBuilder stringBuilder = new StringBuilder();
try {
address = address.replaceAll(" ","%20");
HttpPost httppost = new HttpPost("http://maps.google.com/maps/api/geocode/json?address=" + address + "&sensor=false");
HttpClient client = new DefaultHttpClient();
HttpResponse response;
stringBuilder = new StringBuilder();
response = client.execute(httppost);
HttpEntity entity = response.getEntity();
InputStream stream = entity.getContent();
int b;
while ((b = stream.read()) != -1) {
stringBuilder.append((char) b);
}
} catch (ClientProtocolException e) {
} catch (IOException e) {
}
JSONObject jsonObject = new JSONObject();
try {
jsonObject = new JSONObject(stringBuilder.toString());
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return jsonObject;
}
now pass that JSONObject to getLatLong() method like following
现在将JSONObject传递给getLatLong()方法,如下所示
public static boolean getLatLong(JSONObject jsonObject) {
try {
longitute = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lng");
latitude = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lat");
} catch (JSONException e) {
return false;
}
return true;
}
I hope this helps to you nd others..!! Thank you..!!
我希望这对你和其他人有帮助.. !!谢谢..!!
#4
6
The following code will work for google apiv2:
以下代码适用于google apiv2:
public void convertAddress() {
if (address != null && !address.isEmpty()) {
try {
List<Address> addressList = geoCoder.getFromLocationName(address, 1);
if (addressList != null && addressList.size() > 0) {
double lat = addressList.get(0).getLatitude();
double lng = addressList.get(0).getLongitude();
}
} catch (Exception e) {
e.printStackTrace();
} // end catch
} // end if
} // end convertAddress
Where address is the String (123 Testing Rd City State zip) you want to convert to LatLng.
其中address是要转换为LatLng的String(123 Testing Rd City State zip)。
#5
3
This is how you can find the latitude and longitude of where we have click on map.
这是您可以找到我们点击地图的纬度和经度的方法。
public boolean onTouchEvent(MotionEvent event, MapView mapView)
{
//---when user lifts his finger---
if (event.getAction() == 1)
{
GeoPoint p = mapView.getProjection().fromPixels(
(int) event.getX(),
(int) event.getY());
Toast.makeText(getBaseContext(),
p.getLatitudeE6() / 1E6 + "," +
p.getLongitudeE6() /1E6 ,
Toast.LENGTH_SHORT).show();
}
return false;
}
it works well.
它运作良好。
To get the location's address we can use geocoder class.
要获取位置的地址,我们可以使用地理编码器类。
#6
1
An answer to Kandha problem above :
以上Kandha问题的答案:
It throws the "java.io.IOException service not available" i already gave those permission and include the library...i can get map view...it throws that IOException at geocoder...
它抛出“java.io.IOException服务不可用”我已经给了这些权限并包含了库...我可以获得地图视图...它会在地理编码器处抛出IOException ...
I just added a catch IOException after the try and it solved the problem
我在尝试后添加了一个catch IOException,它解决了问题
catch(IOException ioEx){
return null;
}
#7
0
Geocoder coder = new Geocoder(this);
List<Address> addresses;
try {
addresses = coder.getFromLocationName(address, 5);
if (addresses == null) {
}
Address location = addresses.get(0);
double lat = location.getLatitude();
double lng = location.getLongitude();
Log.i("Lat",""+lat);
Log.i("Lng",""+lng);
LatLng latLng = new LatLng(lat,lng);
MarkerOptions markerOptions = new MarkerOptions();
markerOptions.position(latLng);
googleMap.addMarker(markerOptions);
googleMap.animateCamera(CameraUpdateFactory.newLatLngZoom(latLng,12));
} catch (IOException e) {
e.printStackTrace();
}