本文实例讲述了Android双击退出的实现方法。分享给大家供大家参考。具体实现方法如下:
方式一:
重写onBackPressed方法直接监听返回键(建议高版本用2.0以上)
复制代码 代码如下:
@Override
public void onBackPressed() {
long currentTime = System.currentTimeMillis();
if((currentTime-touchTime)>=waitTime) {
//让Toast的显示时间和等待时间相同
Toast.makeText(this, "再按一次退出", (int)waitTime).show();
touchTime = currentTime;
}else {
finish();
}
}
public void onBackPressed() {
long currentTime = System.currentTimeMillis();
if((currentTime-touchTime)>=waitTime) {
//让Toast的显示时间和等待时间相同
Toast.makeText(this, "再按一次退出", (int)waitTime).show();
touchTime = currentTime;
}else {
finish();
}
}
方式二: (推荐使用)
复制代码 代码如下:
long waitTime = 2000;
long touchTime = 0;
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if(event.getAction() == KeyEvent.ACTION_DOWN && KeyEvent.KEYCODE_BACK == keyCode) {
long currentTime = System.currentTimeMillis();
if((currentTime-touchTime)>=waitTime) {
//让Toast的显示时间和等待时间相同
Toast.makeText(this, "再按一次退出", (int)waitTime).show();
touchTime = currentTime;
}else {
finish();
}
return true;
}
return super.onKeyDown(keyCode, event);
}
long touchTime = 0;
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if(event.getAction() == KeyEvent.ACTION_DOWN && KeyEvent.KEYCODE_BACK == keyCode) {
long currentTime = System.currentTimeMillis();
if((currentTime-touchTime)>=waitTime) {
//让Toast的显示时间和等待时间相同
Toast.makeText(this, "再按一次退出", (int)waitTime).show();
touchTime = currentTime;
}else {
finish();
}
return true;
}
return super.onKeyDown(keyCode, event);
}
希望本文所述对大家的Android程序设计有所帮助。