思路:
自里向外移动,当磁头移到最外的磁道并访问后,磁头立即返回到最里的欲访问磁道,即将最小磁道号紧接着最大磁道号构成循环,进行循环扫描
代码如下:
#include<iostream>
#include<cstring>
#include<algorithm>
#include<queue>
#include<cmath>
using namespace std;
int n;
int start;
int xb;
typedef pair<int, int> p;
vector<p> v;
vector<int> seq;
const int INF = 0x3f3f3f3f;
double avgfind;
int main() {
cout << "请输入磁道个数:" << "\n";
cin >> n;
int temp = n;
cout << "请输入开始磁道号:" << "\n";
cin >> start;
int x;
cout << "请依次输入" << n << "个磁道号" << "\n";
for(int i = 1; i <= n; i ++) {
cin >> x;
seq.push_back(x);
}
sort((), ());
if(seq[0] > start) {
v.push_back({seq[0], abs(seq[0] - start)});
avgfind += abs(seq[0] - start);
start = seq[0];
xb = 1;
for(int i = xb; i < (); i ++) {
v.push_back({seq[i], abs(seq[i] - start)});
avgfind += abs(seq[i] - start);
start = seq[i];
}
}
else if(seq[n - 1] < start) {
v.push_back({seq[n - 1], abs(start - seq[n - 1])});
avgfind += abs(start - seq[n - 1]);
xb = n - 2;
start = seq[n - 1];
for(int i = xb; i >= 0; i --) {
v.push_back({seq[i], abs(seq[i] - start)});
avgfind += abs(seq[i] - start);
start = seq[i];
}
} else {
for(int i = 0; i < () - 1; i ++) {
if(seq[i + 1] > start && seq[i] < start) {
v.push_back({seq[i + 1], abs(seq[i + 1] - start)});
avgfind += abs(seq[i + 1] - start);
start = seq[i + 1];
xb = (i + 2 > ()) ? () : (i + 2);
break;
}
}
for(int i = xb; i < (); i ++) {
v.push_back({seq[i], abs(seq[i] - start)});
avgfind += abs(seq[i] - start);
start = seq[i];
}
for(int i = 0; i <= xb - 2; i ++) {
v.push_back({seq[i], abs(seq[i] - start)});
avgfind += abs(seq[i] - start);
start = seq[i];
}
}
cout << "\n";
cout << "磁道号\t移动距离" << "\n";
for(int i = 0; i < (); i ++) {
cout << v[i].first << "\t" << v[i].second << "\n";
}
cout << "平均寻道长度:" << "\t";
printf("%.2lf", avgfind / temp);
return 0;
}