如何用C语言实现圈叉游戏（-）

今天情人节，还是在学习C语言

自己写了一遍发现自己写的没有书上的代码更简练

就把书上的代码稍微修改了一下

下面看游戏界面

和昨天的米字棋差不多，有时间会结合米字旗的代码做些修改

上代码：

/*
	井字游戏（也称为圈叉游戏）
*/
#include<>
int main(void){
	int player = 0;
	int winner = 0;
	int choice = 0;
	int row = 0;
	int col = 0;
	int line = 0;

	char board[3][3] = {
		{'1','2','3'},
		{'4','5','6'},
		{'7','8','9'}
	};
	for(int i = 0;i < 9 && winner == 0;i++){
		printf("\n\n");
		printf(" %c | %c | %c \n",board[0][0],board[0][1],board[0][2]);
		printf("---+---+---\n");
		printf(" %c | %c | %c \n",board[1][0],board[1][1],board[1][2]);
		printf("---+---+---\n");
		printf(" %c | %c | %c \n",board[2][0],board[2][1],board[2][2]);
		printf("---+---+---\n");
		player = i % 2 + 1;
		do{
			printf("游戏玩家%d,请下棋:",
					player);
			scanf("%d",&choice);

			row = --choice / 3;
			col = choice % 3;
		}while(choice < 0 || choice > 9 || board[row][col] > '9');
		
		board[row][col] = (player == 1) ? 'X' :'O';
		if(board[0][0] == board[1][1] && board[0][0] == board[2][2]
				|| board[0][2] == board[1][1] && board[0][2] == board[2][0])
					winner == player;
		else
			for(line = 0;line < 3;line++){
				if(board[0][line] == board[1][line] 
						&& board[0][line] == board[2][line] ||
						board[line][0] == board[line][1] 
						&& board[line][0]== board[line][2])
						winner = player;
			}
	}
		printf("\n\n");
		printf(" %c | %c | %c |\n",board[0][0],board[0][1],board[0][2]);
		printf("---+---+---+\n");
		printf(" %c | %c | %c |\n",board[1][0],board[1][1],board[1][2]);
		printf("---+---+---+\n");
		printf(" %c | %c | %c |\n",board[2][0],board[2][1],board[2][2]);
		printf("---+---+---+\n");
		if(winner == 0){
			printf("平局\n");
		}
		else
			printf("恭喜%d获胜\n",winner);
	return 0;
}