方法一:
static String mapSortedByKey(Map<String, String> param) {
StringBuilder stringBuilder = new StringBuilder();
ArrayList<String> keyList = new ArrayList<>(());
(keyList);
for (int i = 0; i < (); i++) {
String key = (i);
if (i == () - 1) {
(key).append("=").append((key, ""));
} else {
(key).append("=").append((key, "")).append("&");
}
}
return ();
}
测试:
Map<String, String> param = new HashMap<>();
("type", "1");
("user_mobile", "2");
("full_name", "3");
("id_no", "4");
("secret", "5");
(mapSortedByKey(param));
方法二:使用treeMap直接变为有序的map
static void sortMap(Map<String, String> param) {
TreeMap<String, String> paramTreeMap = new TreeMap<>(param);
(paramTreeMap);
}
public static void main(String[] args) {
HashMap<String, String> paramHashMap = new HashMap<String, String>() {
{
put("type", "1");
put("user_mobile", "2");
put("full_name", "3");
put("id_no", "4");
put("secret", "5");
}
};
sortMap(paramHashMap);
}