In Xcode 6 (beta 4 6A267n), I added a Framework (selecting Swift as the language) and the framework header has this comment: // In this header, you should import all the public headers of your framework using statements like #import
在Xcode 6（beta 4 6A267n）中，我添加了一个Framework（选择Swift作为语言），框架头文件有以下注释：//在此标题中，您应该使用#import之类的语句导入框架的所有公共头文件
Through SO I found that you have to append "-Swift" to your header file name, however I was not able to get this to work.
通过SO，我发现你必须将“-Swift”附加到你的头文件名，但是我无法让它工作。
I've also added $(SRCROOT) to my header search path.
我还在我的标题搜索路径中添加了$（SRCROOT）。
1 个解决方案
#1
11
It sounds like you are trying to create your own Swift library? In which case, you do not need to create an external interface as described here:
听起来你正在尝试创建自己的Swift库？在这种情况下，您不需要创建如下所述的外部接口：
Swift：如何为静态库创建外部接口（Objective-C .h中的公共头模拟）
With Swift you identify your public interface by marking classes and methods as public.
使用Swift，您可以通过将类和方法标记为公共来标识您的公共接口。
The header that has the -Swift suffix is a bridging header and is what you use to bridge Objective-C code so that it can be used in your Swift application.
具有-Swift后缀的标头是桥接标头，用于桥接Objective-C代码，以便可以在Swift应用程序中使用它。
#1
11
It sounds like you are trying to create your own Swift library? In which case, you do not need to create an external interface as described here:
听起来你正在尝试创建自己的Swift库？在这种情况下，您不需要创建如下所述的外部接口：
Swift：如何为静态库创建外部接口（Objective-C .h中的公共头模拟）
With Swift you identify your public interface by marking classes and methods as public.
使用Swift，您可以通过将类和方法标记为公共来标识您的公共接口。
The header that has the -Swift suffix is a bridging header and is what you use to bridge Objective-C code so that it can be used in your Swift application.
具有-Swift后缀的标头是桥接标头，用于桥接Objective-C代码，以便可以在Swift应用程序中使用它。