如何在移动时访问SKSpriteNode子类的对象（Swift）

I am confused with the objects of my class Card that is the subclass of SKSpriteNode. How do I get access to these objects when a user move them. So far I can only access SKNode objects overriding touchesEnded function.

我对我的类Card的对象感到困惑,它是SKSpriteNode的子类。如何在用户移动这些对象时访问这些对象。到目前为止,我只能访问覆盖touchesEnded函数的SKNode对象。

override func touchesEnded(touches: Set<UITouch>, withEvent event: UIEvent?) {
    let touch : UITouch = touches.first as UITouch!
    let touchLocation = touch.locationInNode(self)
    touchedNode = self.nodeAtPoint(touchLocation)
    touchedNode.position = CGPoint(x: size.width * 0.5, y: size.height * 0.5)
    touchedNode.zPosition = 0
}

I need to know what object the user is moving but in this case when touchedNode is an object of SKNode class (not my Card object class) I am not able to figure that out.

我需要知道用户正在移动的对象,但在这种情况下,当touchNode是SKNode类的对象(不是我的Card对象类)时,我无法弄明白。

1 个解决方案

#1

The is operator is exactly what you need.

运算符正是您所需要的。

The is operator compares the types of the two operands. If they are of the same type, or one is a subclass of the other, the expression evaluates to true.

运算符比较两个操作数的类型。如果它们属于同一类型,或者一个是另一个的子类,则表达式的计算结果为true。

So you can check it like this:

所以你可以这样检查:

if touchedNode is Card {
    // do stuff
}

Now what you might want to do is that if touchedNode is really a Card, I want to use the methods I defined in the Card class on the touchedNode.

现在您可能想要做的是,如果被触摸的节点实际上是一张卡片,我想使用我在touchNode上的Card类中定义的方法。

To do this, you need to cast the touchedObject to Card:

为此,您需要将被触摸的对象转换为卡:

let cardNode = touchedNode as! Card

Then you can call your methods on cardNode!

然后你可以在cardNode上调用你的方法!

#1