import numpy as np
k = np.matrix([[1, 2, 3, 4],
[5, 6, 7, 8],
[9, 10, 11, 12]])
print(np.shape(k)) # 输出(3,4)表示矩阵为3行4列
print(k.shape[0]) # shape[0]输出3,为矩阵的行数
print(k.shape[1]) # 同理shape[1]输出列数
- 1
- 2
- 3
- 4
- 5
- 6
- 7