Python Pandas：如何从数据帧的索引中获取行名？

So assume I have a dataframe with rownames that aren't a column of their own per se such as the following:

因此，假设我有一个带有rownames的数据框，这些数据框本身不是它们自己的列，如下所示：

        X  Y
 Row 1  0  5
 Row 2  8  1
 Row 3  3  0

How would I extract these row names as a list, if I have their index? For example, it would look something like:

如果我有它们的索引，我如何将这些行名称提取为列表？例如，它看起来像：

function_name(dataframe[indices])
> ['Row 1', 'Row 2']

Thanks for your help!

谢谢你的帮助！

4 个解决方案

#1

df.index

outputs the row names as pandas Index object. For a list,

输出行名称为pandas Index对象。对于列表，

list(df.index)

lastly, the index supports label slicing similar to columns

最后，索引支持类似于列的标签切片

df.index['Row 2':'Row 5']

#2

If you want to pull out only the index values for certain integer-based row-indices, you can do something like the following using the iloc method:

如果只想拉出某些基于整数的行索引的索引值，可以使用iloc方法执行以下操作：

In [28]: temp
Out[28]:
       index                 time  complete
row_0      2  2014-10-22 01:00:00         0
row_1      3  2014-10-23 14:00:00         0
row_2      4  2014-10-26 08:00:00         0
row_3      5  2014-10-26 10:00:00         0
row_4      6  2014-10-26 11:00:00         0

In [29]: temp.iloc[[0,1,4]].index
Out[29]: Index([u'row_0', u'row_1', u'row_4'], dtype='object')

In [30]: temp.iloc[[0,1,4]].index.tolist()
Out[30]: ['row_0', 'row_1', 'row_4']

#3

this seems to work fine :

这似乎工作正常：

dataframe.axes[0].tolist()

dataframe.axes [0] .tolist（）

#4

if you want to get the index values, you can simply do:

如果你想获得索引值，你可以简单地做：

dataframe.index

dataframe.index

this will output a pandas.core.index

这将输出一个pandas.core.index

#1

df.index