Python dataFrame 行列遍历

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• iteritems():按列遍历，将DataFrame的每一列迭代为(列名, Series)对，可以通过row[index]对元素进行访问。

示例数据

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import pandas as pd   inp = [{'c1':10, 'c2':100}, {'c1':11, 'c2':110}, {'c1':12, 'c2':123}] df = (inp)   print(df)

import pandas as pd inp = [{'c1':10, 'c2':100}, {'c1':11, 'c2':110}, {'c1':12, 'c2':123}] df = (inp) print(df)

按行遍历iterrows():

1 2	for index, row in ():  print(index) # 输出每行的索引值

for index, row in (): print(index) # 输出每行的索引值

row[‘name']

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# 对于每一行，通过列名name访问对应的元素 for row in ():  print(row['c1'], row['c2']) # 输出每一行

# 对于每一行，通过列名name访问对应的元素 for row in (): print(row['c1'], row['c2']) # 输出每一行

按行遍历itertuples():

getattr(row, ‘name')

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1 2	for row in ():  print(getattr(row, 'c1'), getattr(row, 'c2')) # 输出每一行

for row in (): print(getattr(row, 'c1'), getattr(row, 'c2')) # 输出每一行

按列遍历iteritems():

 

1 2	for index, row in ():  print(index) # 输出列名

for index, row in (): print(index) # 输出列名

 

1 2	for row in ():  print(row[0], row[1], row[2]) # 输出各列

for row in (): print(row[0], row[1], row[2]) # 输出各列