题意:求二维矩阵中往8个方向移动的话,从左上方到右下方移动的最短路径
https://leetcode.com/problems/shortest-path-in-binary-matrix/description/
解答:bfs易得
class Solution {
public:
int shortestPathBinaryMatrix(vector<vector<int>>& grid) {
int m = grid.size();
int n = grid[0].size();
int ret = 0;
vector<vector<int>> vis(m, vector<int>(n, 0));
if(grid[0][0] == 1 || grid[m-1][n-1] == 1) {
return -1;
}
int x[] = {1, 1, 0, -1, -1, -1, 0, 1};
int y[] = {0, 1, 1, 1, 0,-1, -1 , -1};
queue<pair<int, int>> q;
q.push({0,0});
vis[0][0] = 1;
while(q.size()) {
int qS = q.size();
for(int i = 0; i < qS; i++) {
auto node = q.front();
q.pop();
if (node.first == m-1 && node.second == n-1)
return ret+1;
for (int k = 0 ; k < 8; k++) {
int dx = node.first + x[k];
int dy = node.second + y[k];
if(dx >= 0 && dx < m && dy >= 0 && dy < n && grid[dx][dy] == 0 && vis[dx][dy] == 0) {
q.push({dx,dy});
vis[dx][dy] = 1;
}
}
}
ret += 1;
}
return -1;
}
};