本文实例为大家分享了简单的Python登录验证，供大家参考，具体内容如下
编写登录接口
要求：1、输入用户名密码
2、认证成功后显示欢迎信息
3、输错三次后锁定
#coding=utf-8
__author__ = 'wangwc'
import sys,os
count = 0
locked = 0
mark_user = 0
mark_passwd = 0
#获取路径
def cur_file_dir():
path = [0]
if (path):
return path
elif (path):
return (path)
#print (cur_file_dir())
path = cur_file_dir()
#print(path)
path1 = ("\\",'/') + '/'
#print (path1)
#path2 = path1 + '/'
#循环输入
while count < 3:
name = input("Username:").strip()
if len(name) == 0:
print ("Username can not be empty....")
continue
key = input("Password:").strip()
if len(key) == 0:
print("The password can not be empty!Try again...")
continue
f = open(path1 + "","r")
userlist = ()
for user in userlist:
if () == name:
mark_user = 1
()
if mark_user == 1:
f = open(path1 + "%s_lock.txt" %(name),"r")
locked = int(().strip())
()
else:
print ("Username or Passsord wrong....")
break
if locked == 1:
print("Sorry, the username had been locked!!!Please call the system administrator...")
else:
f = open (path1 + "%s_passwd.txt" %(name),"r")
passwd = (().strip())
if () == key:
mark_passwd = 1
if mark_user == 1 and mark_passwd == 1:
f = open("%s_count.txt" %(name),"w")
("0")
()
print("%s,welcome BABY!" %(name) )
#input('Press Enter to exit')
else:
f = open("%s_count.txt" %(name),"r")
count = int((().strip()))
()
count +=1
f = open("%s_count.txt" %(name),"w")
(str(count))
()
print ("Username or password wrong!And the username '%s' has %d more chances to retry!" %(name,3 - count))
if(count == 3):
print ("'%s' has been locked!!!" %(name))
if (path1 + "%s_lock.txt" %(name)):
fobj = open(path1 + "%s_lock.txt" %(name),"w")
("1\n")
else:
print ("Username or password wrong!")
continue
以上就是本文的全部内容，希望对大家的学习有所帮助。
本文标题: Python实现简单登录验证
本文地址: /jiaoben/python/