题目链接:654. 最大二叉树
文档讲解: 代码随想录
class Solution(object):
def mergeTrees(self, root1, root2):
"""
:type root1: TreeNode
:type root2: TreeNode
:rtype: TreeNode
"""
if not root1:
return root2
if not root2:
return root1
root1.val += root2.val
root1.left = self.mergeTrees(root1.left, root2.left)
root1.right = self.mergeTrees(root1.right, root2.right)
return root1
class Solution(object):
def mergeTrees(self, root1, root2):
"""
:type root1: TreeNode
:type root2: TreeNode
:rtype: TreeNode
"""
if not root1:
return root2
if not root2:
return root1
#新建一个node
node = TreeNode(0)
node.val = root1.val + root2.val
node.left = self.mergeTrees(root1.left,root2.left)
node.right = self.mergeTrees(root1.right, root2.right)
return node
迭代法:
class Solution(object):
def mergeTrees(self, root1, root2):
"""
:type root1: TreeNode
:type root2: TreeNode
:rtype: TreeNode
"""
if not root1:
return root2
if not root2:
return root1
queue = collections.deque()
queue.append(root1)
queue.append(root2)
while queue:
node1 = queue.popleft()
node2 = queue.popleft()
if node1.left and node2.left:
queue.append(node1.left)
queue.append(node2.left)
if node1.right and node2.right:
queue.append(node1.right)
queue.append(node2.right)
node1.val += node2.val
if not node1.left and node2.left:
node1.left = node2.left
if not node1.right and node2.right:
node1.right = node2.right
return root1
class Solution(object):
def mergeTrees(self, root1, root2):
"""
:type root1: TreeNode
:type root2: TreeNode
:rtype: TreeNode
"""
if not root1:
return root2
if not root2:
return root1
queue = deque()
queue.append((root1, root2))
while queue:
node1, node2 = queue.popleft()
node1.val += node2.val
if node1.left and node2.left:
queue.append((node1.left, node2.left))
elif not node1.left:
node1.left = node2.left
if node1.right and node2.right:
queue.append((node1.right, node2.right))
elif not node1.right:
node1.right = node2.right
return root1