Im new to programming, I have an assignment that asks to create a 2d-array from a 1d array. I came up with this (no help from any outside sources because it takes away the learning experience). It works for our professors test inputs, I was just wondering is this an ugly/inefficient solution.
我是编程新手,我有一个任务,要求从1d数组创建一个二维数组。我想出了这个(没有任何外部来源的帮助,因为它带走了学习经验)。它适用于我们的教授测试输入,我只是想知道这是一个丑陋/低效的解决方案。
function twoDArray(arr, lenSubArray) {
var newArr = [];
var placeHolder = 0;
var leftOver = 0;
for (var i = 1; i < arr.length + 1; i++) {
/* if i is a multiple of the specified sub-array size
then add the elements from placeHolder to i
*/
if (i % lenSubArray === 0) {
newArr.push(arr.slice(placeHolder, i));
placeHolder += lenSubArray;
leftOver++; // tells us how many sub-arrays were created
}
}
/* if original array is not divisible by the length of the specified sub-array
then there will be left over values. Retrieve these values and create an
array out of them and add them to the 2d array.
*/
if (!(arr.length % lenSubArray === 0)) {
/* sub-array count multiplied by the length of each
sub-array gives us the right index to retrieve remaining values
*/
leftOver = (leftOver * lenSubArray);
newArr.push(arr.slice(leftOver))
}
return newArr;
}
Test input: twoDArray([1, 2, 3, 4, 5], 3) output would be: [[1, 2, 3], [4, 5]]
测试输入:twoDArray([1,2,3,4,5],3)输出将是:[[1,2,3],[4,5]]
3 个解决方案
#1
1
you're way too complicated:
你太复杂了:
- create a result-array
- push slices from
i
toi+lenSubArray
- increment
i
bylenSubArray
创建一个结果数组
将切片从i推送到i + lenSubArray
通过lenSubArray递增i
and slice is smart enough to properly handle the end of the Array
和slice足够聪明,可以正确处理数组的结尾
function twoDArray(arr, lenSubArray) {
var i = 0, result = [];
while(i < arr.length)
result.push( arr.slice(i, i+=lenSubArray) );
return result;
}
#2
1
You could use Array#reduce
and build new arrays based on the index.
您可以使用Array#reduce并根据索引构建新数组。
function twoDArray(array, length) {
return array.reduce(function (r, a, i) {
i % length ? r[r.length - 1].push(a) : r.push([a]);
return r;
}, []);
}
console.log(twoDArray([1, 2, 3, 4, 5], 3));
#3
0
You do not need to iterate over an array. You can use Array.prototype.slice
function instead.
您不需要遍历数组。您可以使用Array.prototype.slice函数。
function twoDArray(a, b){
return (Array(Math.ceil(a.length / b)) + '').split(',').map(function(c, d){
return a.slice(b * d, b * (d + 1));
});
}
Here is how you call it
这就是你怎么称呼它
var a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12];
console.log(twoDArray(a, 3));
// Output:
// [
// [1, 2, 3],
// [4, 5, 6],
// [7, 8, 9],
// [10, 11, 12]
// ]
#1
1
you're way too complicated:
你太复杂了:
- create a result-array
- push slices from
i
toi+lenSubArray
- increment
i
bylenSubArray
创建一个结果数组
将切片从i推送到i + lenSubArray
通过lenSubArray递增i
and slice is smart enough to properly handle the end of the Array
和slice足够聪明,可以正确处理数组的结尾
function twoDArray(arr, lenSubArray) {
var i = 0, result = [];
while(i < arr.length)
result.push( arr.slice(i, i+=lenSubArray) );
return result;
}
#2
1
You could use Array#reduce
and build new arrays based on the index.
您可以使用Array#reduce并根据索引构建新数组。
function twoDArray(array, length) {
return array.reduce(function (r, a, i) {
i % length ? r[r.length - 1].push(a) : r.push([a]);
return r;
}, []);
}
console.log(twoDArray([1, 2, 3, 4, 5], 3));
#3
0
You do not need to iterate over an array. You can use Array.prototype.slice
function instead.
您不需要遍历数组。您可以使用Array.prototype.slice函数。
function twoDArray(a, b){
return (Array(Math.ceil(a.length / b)) + '').split(',').map(function(c, d){
return a.slice(b * d, b * (d + 1));
});
}
Here is how you call it
这就是你怎么称呼它
var a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12];
console.log(twoDArray(a, 3));
// Output:
// [
// [1, 2, 3],
// [4, 5, 6],
// [7, 8, 9],
// [10, 11, 12]
// ]