java,从键盘输入个数不确定的整数,并判断输入的正数和负数的个数,输入0时结束程序。
package study01; import java.util.Scanner; public class Test { public static void main(String[] args) { Scanner sc = new Scanner(System.in); //正数的个数 int count1 = 0; //负数的个数 int count2 = 0; int input = sc.nextInt(); while (input != 0) { if (input > 0) { count1++; } else { count2++; } input = sc.nextInt(); } System.out.println("正数的个数为" + count1 + "," + "负数的个数为" + count2); } }
结果如下:
13
-2
-4
11
-6
0
正数的个数为2,负数的个数为3