本文实例讲述了C#线程队列用法。分享给大家供大家参考。具体如下：
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using System;
using System.Collections.Generic;
using System.Text;
using System.Threading;
namespace ThreadPro
{
class Program
{
static Mutex gM1;
static Mutex gM2;
const int ITERS = 100;
static AutoResetEvent Event1 = new AutoResetEvent(false);
static AutoResetEvent Event2 = new AutoResetEvent(false);
static AutoResetEvent Event3 = new AutoResetEvent(false);
static AutoResetEvent Event4 = new AutoResetEvent(false);
static void Main(string[] args)
{
Console.WriteLine("Mutex Sample ");
//创建一个Mutex对象，并且命名为MyMutex
gM1 = new Mutex(true, "MyMutex");
//创建一个未命名的Mutex 对象.
gM2 = new Mutex(true);
Console.WriteLine(" - Main Owns gM1 and gM2");
AutoResetEvent[] evs = new AutoResetEvent[4];
evs[0] = Event1; //为后面的线程t1,t2,t3,t4定义AutoResetEvent对象
evs[1] = Event2;
Program tm = new Program();
Thread t1 = new Thread(new ThreadStart(tm.t1Start));
Thread t2 = new Thread(new ThreadStart(tm.t2Start));
Thread t3 = new Thread(new ThreadStart(tm.t3Start));
Thread t4 = new Thread(new ThreadStart(tm.t4Start));
t1.Start();// 使用Mutex.WaitAll()方法等待一个Mutex数组中的对象全部被释放
t2.Start();// 使用Mutex.WaitOne()方法等待gM1的释放
t3.Start();// 使用Mutex.WaitAny()方法等待一个Mutex数组中任意一个对象被释放
t4.Start();// 使用Mutex.WaitOne()方法等待gM2的释放
Thread.Sleep(2000);
Console.WriteLine(" - Main releases gM1");
gM1.ReleaseMutex(); //线程t2,t3结束条件满
Thread.Sleep(1000);
Console.WriteLine(" - Main releases gM2");
gM2.ReleaseMutex(); //线程t1,t4结束条件满足
//等待所有四个线程结束
WaitHandle.WaitAll(evs);
Console.WriteLine(" Mutex Sample");
Console.ReadLine();
}
public void t1Start()
{
Console.WriteLine("方法一运行, Mutex.WaitAll(Mutex[])");
Mutex[] gMs = new Mutex[2];
gMs[0] = gM1;//创建一个Mutex数组作为Mutex.WaitAll()方法的参数
gMs[1] = gM2;
Mutex.WaitAll(gMs);//等待gM1和gM2都被释放
gM1.ReleaseMutex(); //修正上一次出现的错误
gM2.ReleaseMutex(); //修正上一次出现的错误
Thread.Sleep(2000);
Console.WriteLine("方法一完毕，WaitAll(Mutex[]) satisfied");
Event1.Set(); //线程结束，将Event1设置为有信号状态
}
public void t2Start()
{
Console.WriteLine("方法二运行, gM1.WaitOne( )");
gM1.WaitOne();//等待gM1的释放
gM1.ReleaseMutex(); //修正上一次出现的错误
Console.WriteLine("方法二完毕, gM1.WaitOne( ) satisfied");
Event2.Set();//线程结束，将Event2设置为有信号状态
}
public void t3Start()
{
Console.WriteLine("t3Start started, Mutex.WaitAny(Mutex[])");
Mutex[] gMs = new Mutex[2];
gMs[0] = gM1;//创建一个Mutex数组作为Mutex.WaitAny()方法的参数
gMs[1] = gM2;
Mutex.WaitAny(gMs);//等待数组中任意一个Mutex对象被释放
gM1.ReleaseMutex(); //修正上一次出现的错误
Console.WriteLine("t3Start finished, Mutex.WaitAny(Mutex[])");
Event3.Set();//线程结束，将Event3设置为有信号状态
}
public void t4Start()
{
Console.WriteLine("t4Start started, gM2.WaitOne( )");
gM2.WaitOne();//等待gM2被释放
gM2.ReleaseMutex(); //修正上一次出现的错误
Console.WriteLine("t4Start finished, gM2.WaitOne( )");
Event4.Set();//线程结束，将Event4设置为有信号状态
}
}
}
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希望本文所述对大家的C#程序设计有所帮助。