C++实现矩阵对称正交化的示例代码

1.python代码

import numpy as np
import pandas as pd
df=pd.DataFrame()
df['fac_01']=(34, 45, 65)
df['fac_02']=(56, 25, 94)
print(df)
print('------------------矩阵的特征跟D、和特征向量U-----------------------')
D,U=np.linalg.eig(np.dot(df.T, df)) # 求矩阵的特征跟D、和特征向量U
print(D,U,sep='\n')
print('\n------------------对角矩阵-----------------------')
print(np.diag(D**(-0.5)))
print('\n------------------对称正交后的矩阵-----------------------')
S = np.dot(np.dot(U, np.diag(D**(-0.5))), U.T) # 求过渡矩阵S = U* DEx *U'
F_hat = np.dot(df, S) # 求对称正交后的矩阵
print(F_hat)

2.C++的Eigen库实现

#include "Eigen/Dense"
using namespace Eigen;
int main()
{
  //初始化
  MatrixXf A(3, 2);
  A(0,0) = 34;A(0,1) = 56;
  A(1,0) = 45;A(1,1) = 25;
  A(2,0) = 65;A(2,1) = 94;
  //生成正交矩阵
  MatrixXf AEx = A.transpose() * A;
  int nRowSize = AEx.rows();
  int nColSize = AEx.cols();
  //求特征根、特征向量
  SelfAdjointEigenSolver<Matrix2f> eigensolver(AEx);
  MatrixXf D = eigensolver.eigenvalues();
  MatrixXf U = eigensolver.eigenvectors();
  std::cout<<"特征根如下：" <<std::endl;
  nRowSize = D.rows();
  nColSize = D.cols();
  for(size_t i=0; i<nRowSize; i++)
  {
      for(size_t j=0; j<nColSize; j++)
      {
          std::cout<<D(i,j)<<"    ";
      }
      std::cout<<std::endl;
  }
  std::cout<<"特征向量如下：" <<std::endl;
  nRowSize = U.rows();
  nColSize = U.cols();
  for(size_t i=0; i<nRowSize; i++)
  {
      for(size_t j=0; j<nColSize; j++)
      {
          std::cout<<U(i,j)<<"    ";
      }
      std::cout<<std::endl;
  }
  //生成np.diag(D**(-0.5)))对角线矩阵
  MatrixXf DEx(2,2);
  for(size_t i=0; i<2; i++)
  {
      for(size_t j=0; j<2; j++)
      {
          if(i == j)
          {
              DEx(i,j) = pow(D(i,0),-0.5);
          }
          else
          {
              DEx(i,j) = 0;
          }
      }
  }
  nRowSize = DEx.rows();
  nColSize = DEx.cols();
  std::cout<<"对角线矩阵如下：" <<std::endl;
  for(size_t i=0; i<nRowSize; i++)
  {
      for(size_t j=0; j<nColSize; j++)
      {
          std::cout<<DEx(i,j)<<"    ";
      }
      std::cout<<std::endl;
  }
  //生成过度矩阵S
  MatrixXf S = U * DEx * U.transpose();
  //生成正交化矩阵
  MatrixXf R = A * S;
  nRowSize = R.rows();
  nColSize = R.cols();
  std::cout<<"正交化结果如下：" <<std::endl;
  for(size_t i=0; i<nRowSize; i++)
  {
      for(size_t j=0; j<nColSize; j++)
      {
          std::cout<<R(i,j)<<"    ";
      }
      std::cout<<std::endl;
  }
	return 0;
}

3.结果对比

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原文链接：https://blog.csdn.net/cxd1314520/article/details/120271397