Basically I want to be able to invoke a given command, in this case mysql -uanon -ppwd -db mydb -e "select count(*) from table1"
. And then take this commands result (the count on that table) and place it in a variable in bash script. What is the simplest way to achieve this?
基本上我希望能够调用给定的命令,在这种情况下mysql -uanon -ppwd -db mydb -e“从table1中选择count(*)”。然后获取此命令结果(该表上的计数)并将其放在bash脚本中的变量中。实现这一目标的最简单方法是什么?
2 个解决方案
#1
40
You most likely want to use batch mode (-B) and disable column names (--disable-column-names) for non-interactive mysql output:
您很可能希望使用批处理模式(-B)并禁用非交互式mysql输出的列名(--disable-column-names):
out=$(mysql -B -db mydb -uanon -ppwd --disable-column-names -e "select count(*) from table1";)
#2
14
$ A=$(mysql -uanon -ppwd -db mydb -e "select count(*) from table1")
$ echo $A
In other words, use the $() syntax.
换句话说,使用$()语法。
#1
40
You most likely want to use batch mode (-B) and disable column names (--disable-column-names) for non-interactive mysql output:
您很可能希望使用批处理模式(-B)并禁用非交互式mysql输出的列名(--disable-column-names):
out=$(mysql -B -db mydb -uanon -ppwd --disable-column-names -e "select count(*) from table1";)
#2
14
$ A=$(mysql -uanon -ppwd -db mydb -e "select count(*) from table1")
$ echo $A
In other words, use the $() syntax.
换句话说,使用$()语法。