![[leetcode-543-Diameter of Binary Tree] [leetcode-543-Diameter of Binary Tree]](https://image.shishitao.com:8440/aHR0cHM6Ly9ia3FzaW1nLmlrYWZhbi5jb20vdXBsb2FkL2NoYXRncHQtcy5wbmc%2FIQ%3D%3D.png?!?w=700&webp=1)
Given a binary tree, you need to compute the length of the diameter of the tree.
The diameter of a binary tree is the length of the longest path between any two nodes in a tree.
This path may or may not pass through the root.
Example:
Given a binary tree
1
/ \
2 3
/ \
4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
思路:
求二叉树的高度,左子树的高度加上右子树的高度就为最大的直径。
int height(TreeNode* root, int& diameter)
{
if (root == NULL) return ;
int left = height(root->left, diameter);
int right = height(root->right, diameter);
diameter = max(diameter, left + right);
return + max(left, right);
}
int diameterOfBinaryTree(TreeNode* root)
{
int diameter = ;
height(root, diameter);
return diameter;
}
参考: