problem
429. N-ary Tree Level Order Traversal
solution1:Iteration
/*
// Definition for a Node.
class Node {
public:
int val;
vector<Node*> children; Node() {} Node(int _val, vector<Node*> _children) {
val = _val;
children = _children;
}
};
*/
class Solution {
public:
vector<vector<int>> levelOrder(Node* root) {
if(root==NULL) return vector<vector<int>>();//
vector<vector<int>> res;
queue<Node*> q;
q.push(root);
while(!q.empty())
{
int size = q.size();
vector<int> curLevel;
for(int i=; i<size; ++i)
{
Node* tmp = q.front();
q.pop();
curLevel.push_back(tmp->val);
for(auto a:tmp->children)
{
q.push(a);
}
}
res.push_back(curLevel);
}
return res; }
};
参考
1. Leetcode_429. N-ary Tree Level Order Traversal;
完