
Given a sorted integer array without duplicates, return the summary of its ranges.
For example, given [0,1,2,4,5,7]
, return ["0->2","4->5","7"].
思想很简单 逐个比较前后两个数的差值。
class Solution {
public:
vector<string> summaryRanges(vector<int>& nums) {
vector<string> res ;
if(nums.size()< ) return res;
int i = ;
int n = nums.size();
while(i<n)
{
int j = ;
while(i+j<n && nums[i] == nums[i+j]-j) ++j;
res.push_back(j<=?to_string(nums[i]):to_string(nums[i])+"->"+to_string(nums[i+j-]));
i = i + j;
}
return res;
}
};