![[leetcode]Gas Station @ Python [leetcode]Gas Station @ Python](https://image.shishitao.com:8440/aHR0cHM6Ly9ia3FzaW1nLmlrYWZhbi5jb20vdXBsb2FkL2NoYXRncHQtcy5wbmc%2FIQ%3D%3D.png?!?w=700)
原题地址:https://oj.leetcode.com/problems/gas-station/
题意:
There are N gas stations along a circular route, where the amount of gas at station i is gas[i]
.
You have a car with an unlimited gas tank and it costs cost[i]
of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.
Return the starting gas station's index if you can travel around the circuit once, otherwise return -1.
Note:
The solution is guaranteed to be unique.
解题思路:这道题也很tricky,自己想是很难想出来的。如果sum(gas)<sum(cost)的话,那么一定无解。diff是走完一站邮箱剩下的油,如果加上gas[i]也到不了下一站,那么继续将下一站设置为起点,然后再检查,是不是很巧妙呢?
代码:
class Solution:
# @param gas, a list of integers
# @param cost, a list of integers
# @return an integer
def canCompleteCircuit(self, gas, cost):
if sum(gas) < sum(cost): return -1
n = len(gas)
diff = 0
stationIndex = 0
for i in range(n):
if gas[i]+diff < cost[i]: stationIndex = i+1; diff = 0
else: diff += gas[i]-cost[i]
return stationIndex