I'm trying to write a very simple program, I want to print out the sum of all the multiples of 3 and 5 below 100, but, an error keeps accuring, saying "invalid literal for int() with base 10:" my program is as follows:
我在写一个非常简单的程序,我想打印出100以下3和5的所有倍数的和,但是,一个错误一直在出错,说“以10为基数的int()无效文字”我的程序如下:
sum = ""
sum_int = int(sum)
for i in range(1, 101):
if i % 5 == 0:
sum += i
elif i % 3 == 0:
sum += i
else:
sum += ""
print sum
Any help would be much appreciated.
非常感谢您的帮助。
3 个解决方案
#1
10
The ""
are the cause of these problems.
“”是这些问题的原因。
Change
改变
sum = ""
to
来
sum = 0
and get rid of
和摆脱
else:
sum += ""
#2
7
Python is not JavaScript: ""
does not automatically convert to 0
, and 0
does not automatically convert to "0"
.
Python不是JavaScript:“”不会自动转换为0,而0不会自动转换为“0”。
Your program also seems to be confused between printing the sum of all the multiples of three and five and printing a list of all the numbers which are multiples of three and five.
您的程序似乎还混淆了打印所有3和5的倍数和打印所有3和5的倍数的所有数字的列表。
#3
3
Ok, I'm new to Python so I was doing quite a few silly things; anyway, I think I've worked it out now.
我对Python不熟,所以我做了一些傻事;不管怎样,我想我已经算出来了。
sum = 0
for i in range(1, 1001):
if i % 5 == 0:
sum += i
elif i % 3 == 0:
sum += i
print sum
#1
10
The ""
are the cause of these problems.
“”是这些问题的原因。
Change
改变
sum = ""
to
来
sum = 0
and get rid of
和摆脱
else:
sum += ""
#2
7
Python is not JavaScript: ""
does not automatically convert to 0
, and 0
does not automatically convert to "0"
.
Python不是JavaScript:“”不会自动转换为0,而0不会自动转换为“0”。
Your program also seems to be confused between printing the sum of all the multiples of three and five and printing a list of all the numbers which are multiples of three and five.
您的程序似乎还混淆了打印所有3和5的倍数和打印所有3和5的倍数的所有数字的列表。
#3
3
Ok, I'm new to Python so I was doing quite a few silly things; anyway, I think I've worked it out now.
我对Python不熟,所以我做了一些傻事;不管怎样,我想我已经算出来了。
sum = 0
for i in range(1, 1001):
if i % 5 == 0:
sum += i
elif i % 3 == 0:
sum += i
print sum